Q/Use the grouped frequency distribution table that yo have already done (in Tutorial No. 1) to calculate thefollowing:(1) Mean(2) Median(3) ModeNotes:1) Write first your frequency distribution table beforyour answer.2) Use table in your answer. Grouped Frequency Distribution to the given data isClass Limits Class Boundaries4.5 – 101.5TallyFrequency5- 10117102 – 198101.5 – 198.5199 – 295198.5 – 295.5296 – 392295.5 – 392.52393 – 489392.5 - 489.5||2490 – 586489.5 - 586.53587 – 683586.5 – 683.51684 - 780683.5 – 780.52

Given table : Class limits Class Boundaries frequency 5 - 101 4.5 - 101.5 17 102 - 198 101.5…

Answered: Q/ Use the grouped frequency…

MATLAB: An Introduction with Applications

6th Edition

ISBN:9781119256830

Author:Amos Gilat

Publisher:Amos Gilat

Chapter1: Starting With Matlab

Section: Chapter Questions

Problem 1P

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Q/ Use the grouped frequency distribution table that yo have already done (in Tutorial No. 1) to calculate the following: (1) Mean (2) Median (3) Mode Notes: 1) Write first your frequency distribution table befor your answer. 2) Use table in your answer.

Grouped Frequency Distribution to the given data is
Class Limits Class Boundaries
4.5 – 101.5
Tally
Frequency
5- 101
17
102 – 198
101.5 – 198.5
199 – 295
198.5 – 295.5
296 – 392
295.5 – 392.5
2
393 – 489
392.5 - 489.5
||
2
490 – 586
489.5 - 586.5
3
587 – 683
586.5 – 683.5
1
684 - 780
683.5 – 780.5
2

Definition Definition Measure of central tendency that is the value that occurs most frequently in a data set. A data set may have more than one mode if multiple categories repeat an equal number of times. For example, in a data set with five item—3, 5, 5, 29, 473—the mode is 5 because it occurs twice and no other value occurs more than once. On a histogram or bar chart, the element with the highest bar represents the mode. Therefore, the mode is sometimes considered the most popular option. The mode is useful for nominal or categorical data (e.g., the most common color car that users purchase), but it is problematic for continuous data because it is more likely not to have any value that is more frequent than the other.

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