Q-Two plates of 50 mm thick and 30 mm thick are to be joined by a lap joint using M12 bolts of grade 4.6 Then the design shear strength of bolt is reduced by (in %)?
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A: The yield strength of steel (Fy) = 248 MPa The ultimate strength of steel (Fu) = 400 MPa The…
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Q: A 12.5 mm x150 mm plate is connected to a gusset plate having a thickness of 9.5 mm.Diameter of…
A: A 12.5 mm x150 mm plate is connected to a gusset plate having a thickness of 9.5 mm.Diameter of bolt…
Q: The plate shown is 8 in wide and 1/2 in thick. The bolts are 7/8 in. The smallest net area (An) of…
A: Given:- width of plate =8 inthickness of plate =1/2 inBolts diameter size = 7/8 inA36 plateTo…
Q: 3. A plate with width of 300mm and thickness of 20mm is to be connected to two plates of the same…
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Q: A 100x100x10mm angle is to be welded to a gusset plate. The angle carries a load of 200 kN applied…
A: weld size = 8 mmload =200 kN Fu = 483.33 MPaAllowable shearing stress through throat of weld = 145…
Q: 2. A steel plate is 360 mm wide and 20 mm thick with four bolts hole into the place as shown in the…
A: Answer Given data b= 360 mmt=20 mmNo. of bolts- 4
Q: Find out the strength and efficiency of a bolted lap joint .The bolts are of 30mm diameter, grade…
A: Diameter of bolt, d= 30 mmDiameter of bolt hole, do=30+2.5=32.5 mmFor bolts of grade 4.6 fub =400…
Q: Compute the maximum acceptable tensile SERVICE LOAD that may act on a single tee section that is…
A: Given- Properties of WT- 12×38Ag=11.2 in2y'=3.0 inbf=8.99 inA992 steel-fy=50 ksiFu=65 ksiLL=3DL
Q: A steel plate is to be attached to a support with three bolts. The cross-sectional area of the plate…
A: We have to find out the minimum bolt diameter required to develop the full strength of the plate.
Q: O Based on bolt capacity in shear. O Based on bolt bearing capacity. ® Based on block shear strength…
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Q: bolted lap joint
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Q: a. Under a heavy vibrating loads it is possible that a fully tensioned bolt may come loose. As a…
A: Under heavy vibration or dynamic loading bolted connections and welded are not preferred. Because…
Q: 4. As shown below, the splicing joint of a beam was made with bearing type high-strength bolts. The…
A: Shear force in connection = 3000 kN Moment connection = 90 kNm Bolts grade = 10.9 Nominal Diameter =…
Q: The given angle bar L125x75x12 with Ag = 2,269 sq.mm. is connected to a gusset plate using 20 mm…
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Q: Two plates each with thicknessF16mm are bolted together with6 -22mm dimater bolts forming a lap…
A: Permissible stress is normally refers the allowable stress or allowable strength is the maximum…
Q: The given plate below with width of 200 mm and thickness of 16 mm is to be connected to two plates…
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Q: A bearing type connection is shown in Figure 3.19. The diameter of A 325 bolts is 22 mm and the A572…
A: Tensile capacity, the maximum load that a material can support without damage when being determined…
Q: 1. A tension member is made of 90 mm thick steel plates 225 mm wide by a lap joint made with three…
A: Given data, Thickness of steel plate (t) = 90mm Width of the plate (B) = 225 mm 3 rows of bolts…
Q: Calculate the tightening torque for an SAE 5, ASTM449, 13UNC grade bolt with a diameter of 1/2 inch.…
A: The application of preload to a fastener by the turning of the fastener's nut. Friction points…
Q: Determine the design tensile strength of the plate (200 × 100) mm connected to a 12 mm thick…
A: Given: The dimension of the plate is 200 mm x 100 mm. The thickness of plate is gusset is 12 mm. The…
Q: Plate connection with bolts with shear strength value T=200 MPA is given in the figure. Determine…
A: It is required to determine the area of the bolt. T=PA Here T is the shear strength, P is the…
Q: The bracket shown in the figure is supported by four 22 mm diameter bolts in single shear. The…
A: The bracket shown in the figure is supported by four 22 mm diameter bolts in single shear. The…
Q: 5. A bolted lap joint shown in the figure below. The bolts are 20mn in dianeter in 23 mm holes. The…
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Q: A channel is used as a tension member with the web of the channel welded to a 9.5 mm thick gusset…
A: To solve these problems, we'll use the Load and Resistance Factor Design (LRFD) approach. LRFD…
Q: A plate 400 x 12 mm is to be connected to a plate of the same width and thickness by 34 mm diameter…
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Q: Determine the design tensile strength of plate (200 x8 mm) connected to 10-mm thick gusset using 20…
A: Given, Yield stress of the plate fy=250 N/mm2 d=20 mm Diameter of the hole do=20+1=21 mm Ultimate…
Q: A 30-mm thick AISI 1020 steel plate is sandwiched between two 10-mm thick 2024-T3 aluminum plates…
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Q: Topic:Bolted Steel Connection - Civil Engineering *Use latest NSCP/NSCP 2015 formula to solve…
A: 8 number of A325 bolts of dia =22 mm.S1 = 40 mm S3 = 50 mm t1 = 16 mmS2 = 80 mm S4 = 100 mm t2 = 12…
Q: Considering the following steel connection. The plates in Pink are 9mm steel plates. The middle…
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Q: Calculate the vaue of b in millimeters. b. Calculate the value of the net area for tension in plates…
A: Tensile stress: - When a body is pulled by applying two equal external forces which is normal to…
Q: Topic:Bolted Steel Connection - Civil Engineering *Use latest NSCP/NSCP 2015 formula to solve…
A: Size of steel plates = 225mm x 10mmRivet diameter = 22mm snug fit in the drilled holeAllowable…
Q: repare an excel file and to find a) area of the bolt, b) Average Shear Stress Bolt c) Bearing Area…
A: Hi! Thank you for the question. We are not allowed to share excel or other files but we can help you…
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- B1 USING NEW NSCP CODES, PLEASE ANSWERPlease answer this question asap!The given plate below with width of 200 mm andthickness of 16 mm is to be connected to two plates ofthe same width with half the thickness by 20 mmdiameter rivets as shown. The rivet hole is 2 mm greaterthan the rivet diameter. Allowable tensile stress on netarea is 0.6Fy. Allowable bearing stress is 1.35Fy. Use a501 plate and a502 gr2 rivet a. Determine maximum load P without exceeding allowable tensile stress on plate b. Determine maximum load P without exceeding allowable shear stress on rivets c. Determine maximum load P without exceeding allowable bearing stress between plates and rivets
- A 3/4 in (thickness) X 5 in (height) steel plate is connected to another one through two bolts of nominal diameter 1/2 in in a zig-zag arrangement as shown. Determine the tensile strength capacity Pu of the connection. Review the three limit-states: (a) yielding in the gross area, (b) rup- ture in the overall net tensile area, and (c) block shear strength.Civil Engineering Base plate bending capacity for tension in 310UB 40.4 column for base plate size 500X250X25 in grade 250 steel, 4-M30 4.6/S holding bolts with hole diameter 33 mm, D=pitch 300 mm, gauge distance C=100 mm design data. Yield strength of plate is 250 MPa 4-BOLT PIN N4. As shown below, the splicing joint of a beam was made with bearing type high-strength bolts. The loads transferred through the joint is V=3000KN, M=90KN.m. The bolts are of grade 10.9, nominal diameter 22mm, effective area Ae=2.45cm2;f=310N/ mm?; f-500N/mm²; End plates made of Q235B steel, thickness 22mm, fe-470N/mm?. Check the strength of this bolt connection. -24mm 35 130 35 80 V 1 og1 081 1 081
- Material Strengths: Fy = 248 MPa, F = 400 MPa For the two lines of bolt holes, the pitch is the value that will give a net area DEFG equal to the one along ABC. The diameter of the holes is 22 mm. The thickness of the plate is 12 mm. Determine the LRFD design tensile strength based on yielding on gross area. D A to 50 1 ÓB 50 50 ic O 410 kN O 464 kN O 446 kN O 401 KN F IG Pitch Pitch KISS|YCompute the maximum acceptable tensile SERVICE LOAD that may act on a single tee section that is connected to a gusset plate using welds 12 inches long, as shown in the figure. The service live load is three times the dead load. Use A992 steel. USE LRFD ONLY, no block shear will occur. What is the Governing Ultimate Tensile Capacity based on Net Fracture Round your answer to 3 decimal places.A plate 400 x 12 mm is to be connected to a plate of the same width and thickness by 34 mm diameter bolts, as shown. The holes are 2 mm larger than the bolt diameter. The plate is A36 steel. Assume allowable tensile stress on net area is .60Fy. It is required to determine the value of b such that the net width along bolts 1-2-3-4 is equal to the net width along bolts 1-2-4. a. calculate the value of b in millimeters. b. Calculate the value of the net area for tension in plates in square millimeters. c. Calculate the value of P so that the allowable tensile stress on net area will not be exceeded. d. Calculate the nominal block shear strength based on possible failure paths
- Give me right solution according to the question... Urgent pleasePLEASE ANSWER ALL OF THIS QUESTION ASAP!!!P-016 Given: R=4m W = 3 kN/m Allowable bolt shear stress, fv = 135 MPa Bolts at "a" and "b" are in single shear. Bolt "c" is in double shear. O O O O 8.94 O What is the required bolt diameter at B in mm? * 10.45 6.32 5.22 13.66 B A 8.50 W = 3 kN/m R=4 Compute the reaction at A in kiloNewtons. *