Q) The position of a particle traveling along a straight line is s(t) = (t- 3t +C) ft, where t is in seconds and C is a constant. If s = 4 ft when t = 0, determine the velocity of the particle when t = 4 s. What is the total distance traveled during the time interval t = 0 to t = 4 s? Also, %3D %3D %3D what is the acceleration when t = 2 s?

Elements Of Electromagnetics
7th Edition
ISBN:9780190698614
Author:Sadiku, Matthew N. O.
Publisher:Sadiku, Matthew N. O.
ChapterMA: Math Assessment
Section: Chapter Questions
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Q) The position of a particle traveling along a straight line is s(t) = (t-
3t +C) ft, where t is in seconds and C is a constant. If s = 4 ft when t
= 0, determine the velocity of the particle when t = 4 s. What is the
total distance traveled during the time interval t = 0 to t = 4 s? Also,
%3D
%3D
%3D
what is the acceleration when t 2 s?
Q)
The acceleration of a particle as it moves along a straight line is given by a= 2t -1. Ifs= 1
and v = 2 when t= 0, determine the particle's velocity and position when t=6 s . Also,
determine the total distance the particle travels during this time period.
The car starts and travels with the speed shown by the v-t graph.
Determine the acceleration and position when t= 7 s and t= 11 s.
v (m/s)
v = 5
v = -t +13
t (s)
9.
13
Transcribed Image Text:3 Q) The position of a particle traveling along a straight line is s(t) = (t- 3t +C) ft, where t is in seconds and C is a constant. If s = 4 ft when t = 0, determine the velocity of the particle when t = 4 s. What is the total distance traveled during the time interval t = 0 to t = 4 s? Also, %3D %3D %3D what is the acceleration when t 2 s? Q) The acceleration of a particle as it moves along a straight line is given by a= 2t -1. Ifs= 1 and v = 2 when t= 0, determine the particle's velocity and position when t=6 s . Also, determine the total distance the particle travels during this time period. The car starts and travels with the speed shown by the v-t graph. Determine the acceleration and position when t= 7 s and t= 11 s. v (m/s) v = 5 v = -t +13 t (s) 9. 13
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