Q: In the figure below, the depth of excavation required to form a cutting at 20 m intervals are 0.000, 0.900, 1.500, 3.200 and 3.300 m. given that the roadway is 5 m wide and 80 m long and the side slopes at an angle 30°, calculate the cross-sectional areas of the cutting and total volume of excavation using trapezoidal rule. Chainage (m) C (m) 3.2m 5m (C/tan 30°) (m) (C/tan 30º) + W (m) 30⁰ ((C/tan 30) + W) xC (m²)
Q: In the figure below, the depth of excavation required to form a cutting at 20 m intervals are 0.000, 0.900, 1.500, 3.200 and 3.300 m. given that the roadway is 5 m wide and 80 m long and the side slopes at an angle 30°, calculate the cross-sectional areas of the cutting and total volume of excavation using trapezoidal rule. Chainage (m) C (m) 3.2m 5m (C/tan 30°) (m) (C/tan 30º) + W (m) 30⁰ ((C/tan 30) + W) xC (m²)
Chapter2: Loads On Structures
Section: Chapter Questions
Problem 1P
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![Q: In the figure below, the depth of excavation required to form a cutting at 20 m intervals are 0.000, 0.900, 1.500, 3.200 and 3.300 m. given that the roadway is 5 m wide and 80 m long and the side slopes at an angle 300, calculate the cross-sectional areas of the
cutting and total volume of excavation using trapezoidal rule.
Chainage
(m)
C (m)
3.2m
5m
(C/tan 30°) (m)
(C/tan 30°) + W
(m)
30⁰
((C/tan 30°) + W) x C (m²)](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2Fe482260c-a481-4036-b56b-ba1151b84d9b%2F128a54d0-017f-43af-bace-225b24c651c6%2Fgqadkuk_processed.png&w=3840&q=75)
Transcribed Image Text:Q: In the figure below, the depth of excavation required to form a cutting at 20 m intervals are 0.000, 0.900, 1.500, 3.200 and 3.300 m. given that the roadway is 5 m wide and 80 m long and the side slopes at an angle 300, calculate the cross-sectional areas of the
cutting and total volume of excavation using trapezoidal rule.
Chainage
(m)
C (m)
3.2m
5m
(C/tan 30°) (m)
(C/tan 30°) + W
(m)
30⁰
((C/tan 30°) + W) x C (m²)
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