Q: find the solution of This system of ordinary differential equations by numerical Euler's method :- Y₁ (t) = y₁ (t) _2 Y₂ (t) + 4 cos (t) - 2 sin (t) » Y₁₂ (0) = + 2 Yz(t) = 3 Y₁₂ (6) - 4 Y ₁₂ (6) + 5 cos(t) — 5 sin (6), Y₂60) = 2

Advanced Engineering Mathematics
10th Edition
ISBN:9780470458365
Author:Erwin Kreyszig
Publisher:Erwin Kreyszig
Chapter2: Second-order Linear Odes
Section: Chapter Questions
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Q: find the solution of This system of ordinary differential
• equations by numerical Euler's method :-
• =
2
Y₁ (t) - Y₁ (t) - 2 Y₂ (t) + 4 cos (t)
= y₁ (t) - 2 Y₂ (t) + 4 cos (t) - 2 sin (t) • Y₁₂ (0) =+
Y₁₂ (t) = 3 Y₁ (t) – 4 Y/₁₂ (6) + 5 cos(t) - 5 sin(t), 1₂60)=2
Transcribed Image Text:COCO التاريخ : / / الموضوع : Q: find the solution of This system of ordinary differential • equations by numerical Euler's method :- • = 2 Y₁ (t) - Y₁ (t) - 2 Y₂ (t) + 4 cos (t) = y₁ (t) - 2 Y₂ (t) + 4 cos (t) - 2 sin (t) • Y₁₂ (0) =+ Y₁₂ (t) = 3 Y₁ (t) – 4 Y/₁₂ (6) + 5 cos(t) - 5 sin(t), 1₂60)=2
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