Q₂: Evaluate 8 dx 6 x + 1

Q: Evaluate [ 1 (x-1)/3 - dx

A: Given data, ∫031x-123

Q: 1 V4–x² 6. 4-x

A:

Q: Evaluate (x² + y²) dxdy

A:

Q: 22ニ」 dx ズ+ぞ

A:

Q: 7x d.x 2)3 (1 – x²)³

A:

Q: 1 dx (2x + 1)4

A: We will use concept of improper integral here.

Q: Evaluate dx. /25 – x²

A: First of all, let x = 5 sin (u) and differentiate w.r.t x on both sides of the equation and find dx.

Q: S Vx8 – 6x6 + 9x4 dx is equal to -

A: The equation of integral is ∫x8-6x6+9x4dx.

Q: 4 dx 16 + x2 -4

A: To find: The integration of ∫-44dx16+x2. Concept used: Integration formula: ∫dxa2+x2=1atan-1xa

Q: Calculate 2 3x-2x²+2 dx. 13 -1

A:

Q: Evaluate: 3 f(-x² + 4x-1)dx 1

A:

Q: (x5 + 3у)dx — хdу —D 0

A:

Q: dx Vx + a + Vx + b

A: Given: The integral is ∫xx+a+x+bdx

Q: | (3 + xx) dx

A:

Q: [e³(5e* + 8) 6 dx.

A: see below the answer and calculation

Q: d. Se-7x+10 dx

A: We have to evaluate the integral.

Q: 3 S x² √9-x² dx

A:

Q: S 9 x²+25 -dx

A:

Q: orea Evaluate the definite integral 2 (9et + 8x)dx using Part 1 of the Fundamental Theorem of…

A:

Q: dx |2+3x-2x² 3

A:

Q: se-2+10 dx V4e

A:

Q: dx L. (x² + 1)(x² + 4)(x² + 9)* 8.

A:

Q: Integrate x sqrt of (x+4) dx using algebraic substitution

A:

Q: Compute 3+r+1 dx x2

A: Given : ∫233x2+2x+1x2dx

Q: dx V4x? +1

A:

Q: Evaluate V25 -4x2" dx

A:

Q: (1 +Iпx) dx x3

A: The given integral is ∫1+ln xx3dx. Here, u=1+ln x  and  v=1x3.

Q: S V2 + 3x da

A: Let 2+3x be t

Q: 4 dx V1- 25x2

A: