Q 3. A spherical charge distribution has a volume charge density which is a function only of r, the distance from the center of the distribution. In other words p = p(r). If p(r) is as given below, determine the Electrid Field as a function of r. Integrate the result to obtain an expression for the electrostatic potential U(r), subject to the restriction that U(0) = 0. p = A/r with A constant for 0 >r> R p= 0 for r > 0.
Q 3. A spherical charge distribution has a volume charge density which is a function only of r, the distance from the center of the distribution. In other words p = p(r). If p(r) is as given below, determine the Electrid Field as a function of r. Integrate the result to obtain an expression for the electrostatic potential U(r), subject to the restriction that U(0) = 0. p = A/r with A constant for 0 >r> R p= 0 for r > 0.
College Physics
11th Edition
ISBN:9781305952300
Author:Raymond A. Serway, Chris Vuille
Publisher:Raymond A. Serway, Chris Vuille
Chapter1: Units, Trigonometry. And Vectors
Section: Chapter Questions
Problem 1CQ: Estimate the order of magnitude of the length, in meters, of each of the following; (a) a mouse, (b)...
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hi please solve this question ( 3 only. ) Please make sure you do calculations for potential. i will rate it if solved quickly.
Please don't solve 1 and 2 , just the 3 one

Transcribed Image Text:Q 1. A circular disk of radius R has a uniform surface charge density o. Find the electric field at a point on
the axis of the disk at a distance z from the plane of the disk.
Q 2. A right circular cylinder of radius R and height L is oriented along the z-axis. It has a nonuniform
volume density of charge given by p(z) = Po+ Bz with reference to a origin at the center of the cylinder.
Find the force on a point charge q placed at the center of the cylinder.
Q 3. A spherical charge distribution has a volume charge density which is a function only of r, the distance
from the center of the distribution. In other words p= p(r). If p(r) is as given below, determine the Electrid
Field as a function of r. Integrate the result to obtain an expression for the electrostatic potential U(r),
subject to the restriction that U(o0) = 0.
p = A/r with A constant for 0 >r>R
p= 0 for r > 0.
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