p(z,y) 0 1 2 X 0 y 0.10 0.03 0.01 1 0.06 0.20 0.07 2 0.06 0.14 0.33 (a) What is P(X = 1 and Y = 1) ? P(X = 1 and Y = 1) = 0.20 (b) Compute P(X ≤ 1 and Y ≤ 1) . P(X ≤ 1 and Y < 1) = (c) Give a word description of the event { X 0 and Y / 0}. O At least one hose is in use at both islands. One hose is in use on both islands. One hose is in use on one island. At most one hose is in use at both islands. Compute the probability of this event. P(X / 0 and Y / 0) =

A First Course in Probability (10th Edition)
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Chapter1: Combinatorial Analysis
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Problem 1.1P: a. How many different 7-place license plates are possible if the first 2 places are for letters and...
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webassign.net
p(I,y)
X
0 1 2
0 0.10 0.03
1 0.06 0.20 0.07
2 0.06 0.14 0.33
(a) What is P(X= 1 and Y = 1)?
0.01
P(X = 1 and Y = 1) = 0.20
(b) Compute P(X ≤ 1 and Y < 1).
P(X ≤ 1 and Y < 1) =
(c) Give a word description of the event { X 0 and Y / 0 }.
At least one hose is in use at both islands.
One hose is in use on both islands.
One hose is in use on one island.
At most one hose is in use at both islands.
Compute the probability of this event.
P(X 0 and Y / 0)
Transcribed Image Text:webassign.net p(I,y) X 0 1 2 0 0.10 0.03 1 0.06 0.20 0.07 2 0.06 0.14 0.33 (a) What is P(X= 1 and Y = 1)? 0.01 P(X = 1 and Y = 1) = 0.20 (b) Compute P(X ≤ 1 and Y < 1). P(X ≤ 1 and Y < 1) = (c) Give a word description of the event { X 0 and Y / 0 }. At least one hose is in use at both islands. One hose is in use on both islands. One hose is in use on one island. At most one hose is in use at both islands. Compute the probability of this event. P(X 0 and Y / 0)
←
M1A3(b) - MATH 142-2_1Q222
webassign.net
P(X 0 and Y # 0) =
(d) Compute the marginal pmf of X.
X
y
Py(y)
+
0
Px(x)
Compute the marginal pmf of Y.
P(X ≤ 1) =
0
Using Px(x), what is P(X ≤ 1)?
1
1
2
2
(e) Are X and Y independent rv's? Explain.
Ox and Y are not independent because P(x, y) + px(x) · py(y).
OX and Y are not independent because P(x, y) = px(x) · Py(y).
OX and Y are independent because P(x, y) = Px(x) · py(y).
OX and Y are independent because P(x, y) / Px(x) · Py(y).
Transcribed Image Text:← M1A3(b) - MATH 142-2_1Q222 webassign.net P(X 0 and Y # 0) = (d) Compute the marginal pmf of X. X y Py(y) + 0 Px(x) Compute the marginal pmf of Y. P(X ≤ 1) = 0 Using Px(x), what is P(X ≤ 1)? 1 1 2 2 (e) Are X and Y independent rv's? Explain. Ox and Y are not independent because P(x, y) + px(x) · py(y). OX and Y are not independent because P(x, y) = px(x) · Py(y). OX and Y are independent because P(x, y) = Px(x) · py(y). OX and Y are independent because P(x, y) / Px(x) · Py(y).
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