P(Z <20) = 0.9952. Then zo = P(Z>20) = 0.6554. Then zo = 0.75 1.02

A First Course in Probability (10th Edition)
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ISBN:9780134753119
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Chapter1: Combinatorial Analysis
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Problem 1.1P: a. How many different 7-place license plates are possible if the first 2 places are for letters and...
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I want to make sure my answers are right here. I am not sure about my last two answers, thank you.

You may need to use the appropriate table (Standard Normal Table) to answer this question.
Given that Z is a standard normal random variable, find the value of zo for each situation.
Round your answers to two decimal places. Don't forget to enter the minus sign if zo is
negative.
P(Z <zo) = 0.2743. Then zo -0.60
=
P(-20 <Z<zo) = 0.9398. Then zo
=
P(-20 <Z<20) = 0.2052. Then zo
=
P(Z <zo) = 0.9952. Then zo
=
P(Z > 20) = 0.6554. Then zo
=
0.75
1.02
1.88
0.26
Transcribed Image Text:You may need to use the appropriate table (Standard Normal Table) to answer this question. Given that Z is a standard normal random variable, find the value of zo for each situation. Round your answers to two decimal places. Don't forget to enter the minus sign if zo is negative. P(Z <zo) = 0.2743. Then zo -0.60 = P(-20 <Z<zo) = 0.9398. Then zo = P(-20 <Z<20) = 0.2052. Then zo = P(Z <zo) = 0.9952. Then zo = P(Z > 20) = 0.6554. Then zo = 0.75 1.02 1.88 0.26
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