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P(X²3) =(₂₂) +0.403 ×0.597 (0) 0.403¹ +0.597" : (5) 10.403" P(x43)-(C)*0.403x0.597 (₂C) -0.403 0.597*(C₂) 0.403* *0.597

P(X²3) =(₂₂) +0.403 ×0.597 (0) 0.403¹ +0.597" : (5) 10.403" P(x43)-(C)*0.403x0.597 (₂C) -0.403 0.597*(C₂) 0.403* *0.597

MATLAB: An Introduction with Applications
MATLAB: An Introduction with Applications
6th Edition
ISBN:9781119256830
Author:Amos Gilat
Publisher:Amos Gilat
Chapter1: Starting With Matlab
Section: Chapter Questions
Problem 1P
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OK C/CE 1 ON/AC 0 2 3 + P(7²3) =(₂₂) *0.403° 0.597 +(0) *0.403 +0.597 +(20.403²0 P(x43)-(C)*0.403x0.597" (C) *0.403 0.597 * ₂.0.403²³ -0.597
Transcribed Image Text:OK C/CE 1 ON/AC 0 2 3 + P(7²3) =(₂₂) *0.403° 0.597 +(0) *0.403 +0.597 +(20.403²0 P(x43)-(C)*0.403x0.597" (C) *0.403 0.597 * ₂.0.403²³ -0.597
40.3% of consumers believe that cash will be obsolete (5.2.2, in the next 20 years. Assume that 7 custo de consumers are randomly selected. Find the probability that fewer than 3 of the selected believe that cash will be obsolete in the next 20 years p=prob of cons. that believe cash will be obsolete p=0.403 n = # of trials n=7 x - binomial (n=¹7, p=0.403) afm a= 1-p=1-0.403= 9 = 0.597 per a P(J(<3) n-x 1 x 0.403 × 597.
Transcribed Image Text:40.3% of consumers believe that cash will be obsolete (5.2.2, in the next 20 years. Assume that 7 custo de consumers are randomly selected. Find the probability that fewer than 3 of the selected believe that cash will be obsolete in the next 20 years p=prob of cons. that believe cash will be obsolete p=0.403 n = # of trials n=7 x - binomial (n=¹7, p=0.403) afm a= 1-p=1-0.403= 9 = 0.597 per a P(J(<3) n-x 1 x 0.403 × 597.
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