please solve using MOMENT AREA METHOD O Pab 2l -b)PL3EIPL?Og =2EIPLPL?16EIPx2(3L² – 4x*) 0 sxs48EI48EI6E 3L – x)Ph(L -9/3LEIPhx(L -x - b)OSxsaPx2GLEI-(21 - a)Pab6L EIE (3a - x) 0SxsaB6EIPa?dn =AE (3L - a)Og =-PaPb (L.at xVPah6EI2EI(21 -b)6LEIPa?(3x- a) a SXSL6EIPh(31-46) if a >bSaerT48EISwl(L'- 21.x +x')Smar384EI- - AEI24EI-(6L – 4Lx+x²)OB =6EI24EISEI2L Ela - 21)² + 2a(a - 21.)x + Lx daer (S2 - 121b+ 84y241. EI(SL - 121b + 8A)384EI(a - 2L)WoOSxsa241. EIif a zbME(6a - 4ax+x) 0sxs a24EIWoa24ET AL - a) Og =-(-L+x)(a - 4Lx + 2x)SanterKET (3L - 2a) if asb 34LET (21. -a")(31 - 2a) if a sb24L. EI6EI24L. EI96EIWpa"24E (4x - a)asxsLda 0.006 522"El360EI(7L* – 102x² + 3x*)at x- 0.51931360LEISio "LSar-0.006 510EI45 EIwoLA120L ET (10L' – 10L²X+5Lx² – x³) | ôp =24EI30EIat xAMax(L-x)6LEIE19 vaMol9/3EI6EIMoLMox?SanerMoLOg =EI16EI3EIMo2EI2EI

Answered: Image /qna-images/answer/51528661-e225-4b9e-99c0-a06a2e9c5955.jpg

Answered: Px :(3L – x) 6EI PL Px PL? (3L² - 4x)…

Px :(3L – x) 6EI PL Px PL? (3L² - 4x) osxs 48EI 3EI 2EI Phx Px2 (L² - -) 6LEI (3a - x) 0sxsa 6EI Pa Pb [L Pa (3L - a) Og = 6EI 6LEI (x-a)' + (L-) 2EI Pa (3x – a) asxsL 6EI as

Structural Analysis

6th Edition

ISBN:9781337630931

Author:KASSIMALI, Aslam.

Publisher:KASSIMALI, Aslam.

Chapter2: Loads On Structures

Section: Chapter Questions

Problem 1P

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Question

please solve using MOMENT AREA METHOD

O Pab 2l -b)
PL
3EI
PL?
Og =
2EI
PL
PL?
16EI
Px2
(3L² – 4x*) 0 sxs
48EI
48EI
6E 3L – x)
Ph(L -
9/3LEI
Phx
(L -x - b)
OSxsa
Px2
GLEI
-(21 - a)
Pab
6L EI
E (3a - x) 0Sxsa
B
6EI
Pa?
dn =AE (3L - a)
Og =-
Pa
Pb (L.
at xV
Pah
6EI
2EI
(21 -b)
6LEI
Pa?
(3x- a) a SXSL
6EI
Ph
(31-46) if a >b
SaerT
48EI
Swl
(L'- 21.x +x')
Smar
384EI
- - AEI
24EI
-(6L – 4Lx+x²)
OB =
6EI
24EI
SEI
2L Ela - 21)² + 2a(a - 21.)x + Lx daer (S2 - 121b+ 84y
241. EI
(SL - 121b + 8A)
384EI
(a - 2L)
Wo
OSxsa
241. EI
if a zb
ME(6a - 4ax+x) 0sxs a
24EI
Woa
24ET AL - a) Og =-
(-L+x)(a - 4Lx + 2x)
Santer
KET (3L - 2a) if asb 34LET (21. -a")
(31 - 2a) if a sb
24L. EI
6EI
24L. EI
96EI
Wpa"
24E (4x - a)
asxsL
da 0.006 522
"
El
360EI
(7L* – 102x² + 3x*)
at x- 0.51931
360LEI
Sio "L
Sar-0.006 510
EI
45 EI
woL
A
120L ET (10L' – 10L²X+5Lx² – x³) | ôp =
24EI
30EI
at xA
Max
(L-x)
6LEI
E19 va
Mol
9/3EI
6EI
MoL
Mox?
Saner
MoL
Og =
EI
16EI
3EI
Mo
2EI
2EI

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