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Put the following statements in order to justify why 5+4n-2n² lim n→∞ 5n² +8n+7 Statements to choose from: Drag these statements to the right column. 5+4n - 2n² lim n→∞ 5n² + 8n +7 = lim (-2) + 4 lim n→∞ : lim n→∞ 2 5 −2+4.0+ 5.0 5+8.0 +7.0 lim (5) + 8 lim n→∞ n→∞ lim n→∞ = lim n→∞ n→∞ n lim n→∞ n² n 8 1² ( 5 + ² + 7 ) n n² n 5+ 4 n n || + 7 lim n→∞ 8 + 5 lim n→∞ 2+ 2+ 5 n² 7 + n n² 5 n² 7 5+ + n n² 5 n² 2+ er 1 n² 1 n²

Put the following statements in order to justify why 5+4n-2n² lim n→∞ 5n² +8n+7 Statements to choose from: Drag these statements to the right column. 5+4n - 2n² lim n→∞ 5n² + 8n +7 = lim (-2) + 4 lim n→∞ : lim n→∞ 2 5 −2+4.0+ 5.0 5+8.0 +7.0 lim (5) + 8 lim n→∞ n→∞ lim n→∞ = lim n→∞ n→∞ n lim n→∞ n² n 8 1² ( 5 + ² + 7 ) n n² n 5+ 4 n n || + 7 lim n→∞ 8 + 5 lim n→∞ 2+ 2+ 5 n² 7 + n n² 5 n² 7 5+ + n n² 5 n² 2+ er 1 n² 1 n²

Calculus: Early Transcendentals
Calculus: Early Transcendentals
8th Edition
ISBN:9781285741550
Author:James Stewart
Publisher:James Stewart
Chapter1: Functions And Models
Section: Chapter Questions
Problem 1RCC: (a) What is a function? What are its domain and range? (b) What is the graph of a function? (c) How...
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(See image for full explanation.) Put the following statements in order to justify the functino given equals -2/5. Basically just put the statements in a sequential order that makes sense.

Put the following statements in order to justify why 5+4n-2n² lim n→∞ 5n² +8n+7 Statements to choose from: Drag these statements to the right column. 5+4n - 2n² lim n→∞ 5n² +8n + 7 = lim (-2) + 4 lim n→∞ 2 5 : lim n→∞x −2+4.0+ 5.0 5+8.0 +7.0 lim (5) + 8 lim n→∞ n→∞ = n→∞ n lim n→∞ lim n→∞ n lim n→∞ n² n 8 1² ( 5 + ² + 7 ) n n² 5+ 4 n n - || + 7 lim n→∞ 8 2+ + 5 lim n→∞ 2+ 5 n² 7 + n n² 2+ 5+ + n io 5 n² 5 n² 7 n² 1 n² 1 n²
Transcribed Image Text:Put the following statements in order to justify why 5+4n-2n² lim n→∞ 5n² +8n+7 Statements to choose from: Drag these statements to the right column. 5+4n - 2n² lim n→∞ 5n² +8n + 7 = lim (-2) + 4 lim n→∞ 2 5 : lim n→∞x −2+4.0+ 5.0 5+8.0 +7.0 lim (5) + 8 lim n→∞ n→∞ = n→∞ n lim n→∞ lim n→∞ n lim n→∞ n² n 8 1² ( 5 + ² + 7 ) n n² 5+ 4 n n - || + 7 lim n→∞ 8 2+ + 5 lim n→∞ 2+ 5 n² 7 + n n² 2+ 5+ + n io 5 n² 5 n² 7 n² 1 n² 1 n²
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