Put the equation y x + 8x + 15 into the form y = (x – h)² + k: Answer: y =

Algebra and Trigonometry (6th Edition)
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Author:Robert F. Blitzer
Publisher:Robert F. Blitzer
ChapterP: Prerequisites: Fundamental Concepts Of Algebra
Section: Chapter Questions
Problem 1MCCP: In Exercises 1-25, simplify the given expression or perform the indicated operation (and simplify,...
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**Problem Statement:**

Transform the equation \( y = x^2 + 8x + 15 \) into the vertex form \( y = (x-h)^2 + k \).

**Answer Form:**

\[ y = \]

**Explanation:**

To convert the quadratic equation from standard form to vertex form, we complete the square.

1. Start with the equation \( y = x^2 + 8x + 15 \).
2. Focus on the \( x^2 + 8x \) part. To complete the square:
   - Take half of the coefficient of \( x \) (which is 8), giving 4, and square it to get 16.
3. Add and subtract 16 inside the equation:
   - \( y = (x^2 + 8x + 16) - 16 + 15 \).
4. Rewrite the quadratic expression as a perfect square:
   - \( y = (x + 4)^2 - 1 \).

Now, the equation is in the vertex form \( y = (x-h)^2 + k \), where \( h = -4 \) and \( k = -1 \).

**Final Answer:**

\[ y = (x+4)^2 - 1 \]
Transcribed Image Text:**Problem Statement:** Transform the equation \( y = x^2 + 8x + 15 \) into the vertex form \( y = (x-h)^2 + k \). **Answer Form:** \[ y = \] **Explanation:** To convert the quadratic equation from standard form to vertex form, we complete the square. 1. Start with the equation \( y = x^2 + 8x + 15 \). 2. Focus on the \( x^2 + 8x \) part. To complete the square: - Take half of the coefficient of \( x \) (which is 8), giving 4, and square it to get 16. 3. Add and subtract 16 inside the equation: - \( y = (x^2 + 8x + 16) - 16 + 15 \). 4. Rewrite the quadratic expression as a perfect square: - \( y = (x + 4)^2 - 1 \). Now, the equation is in the vertex form \( y = (x-h)^2 + k \), where \( h = -4 \) and \( k = -1 \). **Final Answer:** \[ y = (x+4)^2 - 1 \]
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