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Puoor Statement Reasuns 1, AC BC Median CD of AABC 1. 2. Dis the midpoint of AB. 2. 3. Definition of midpoint 4. 5. 3. 4. ZA ZB 6. ACAD ACBD 6. ZCDA 2CDB 7. 2CDA and ZCDB form a linear pair. 6. 7. 8. Linear Pair Postulate 9. Theorem 6.1 10. Definition of perpen- dicular segments 8. 9. 10. CD is perpendicular to AB. 11. 11.

Puoor Statement Reasuns 1, AC BC Median CD of AABC 1. 2. Dis the midpoint of AB. 2. 3. Definition of midpoint 4. 5. 3. 4. ZA ZB 6. ACAD ACBD 6. ZCDA 2CDB 7. 2CDA and ZCDB form a linear pair. 6. 7. 8. Linear Pair Postulate 9. Theorem 6.1 10. Definition of perpen- dicular segments 8. 9. 10. CD is perpendicular to AB. 11. 11.

Elementary Geometry For College Students, 7e
Elementary Geometry For College Students, 7e
7th Edition
ISBN:9781337614085
Author:Alexander, Daniel C.; Koeberlein, Geralyn M.
Publisher:Alexander, Daniel C.; Koeberlein, Geralyn M.
ChapterP: Preliminary Concepts
SectionP.CT: Test
Problem 1CT
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Puoor Statement Reasuns 1. AC BC Median CD of AABC 1. 2. Dis the midpoint of AB. 2. 3. Definition of midpoint 4. 3. 4. ZA ZB 6. ACAD ACBD 6. ZCDA s 2CDB 7, 2CDA andZCDB form a linear pair. 5. 7. 8. Linear Pair Postulate 9. Theorem 61 10. Definition of perpen- dieular segments 8. 9. 10. CD is perpendicular to AB. 11. అ 11.
Transcribed Image Text:Puoor Statement Reasuns 1. AC BC Median CD of AABC 1. 2. Dis the midpoint of AB. 2. 3. Definition of midpoint 4. 3. 4. ZA ZB 6. ACAD ACBD 6. ZCDA s 2CDB 7, 2CDA andZCDB form a linear pair. 5. 7. 8. Linear Pair Postulate 9. Theorem 61 10. Definition of perpen- dieular segments 8. 9. 10. CD is perpendicular to AB. 11. అ 11.
6. The median to the base of an isosceles triangle is the perpendicular bisector of the base. RESTATEMENT Given: Isosceles triangle ABC with AC BC and median CD Prove: CD is the perpendicular bisector of AB. A D
Transcribed Image Text:6. The median to the base of an isosceles triangle is the perpendicular bisector of the base. RESTATEMENT Given: Isosceles triangle ABC with AC BC and median CD Prove: CD is the perpendicular bisector of AB. A D
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