Pulley 151° 72.5 35 kg kg Bench = 0.66 0.325 -Three objects are connected by weightless flexible strings as shown in the figure. The pulley has no appreciable mass or friction, and the string connected to the block on the horizontal bench pulls on the block parallel to the bench surface. The coefficients of friction between the bench and t block on it are u, = 0.66 and Hx =0.325. You observe that this system remains at rest. Answer the following questions. Show all work. Clearly indicate any fundamental principles used. a. Draw a force diagram for the 35 kg block. b. Draw a force diagram for the point connecting the three ropes. c. Calculate the mass of block A.

Pulley 151° 72.5 35 kg kg Bench = 0.66 0.325 -Three objects are connected by weightless flexible strings as shown in the figure. The pulley has no appreciable mass or friction, and the string connected to the block on the horizontal bench pulls on the block parallel to the bench surface. The coefficients of friction between the bench and t block on it are u, = 0.66 and Hx =0.325. You observe that this system remains at rest. Answer the following questions. Show all work. Clearly indicate any fundamental principles used. a. Draw a force diagram for the 35 kg block. b. Draw a force diagram for the point connecting the three ropes. c. Calculate the mass of block A.

College Physics

11th Edition

ISBN:9781305952300

Author:Raymond A. Serway, Chris Vuille

Publisher:Raymond A. Serway, Chris Vuille

Chapter1: Units, Trigonometry. And Vectors

Section: Chapter Questions

Problem 1CQ: Estimate the order of magnitude of the length, in meters, of each of the following; (a) a mouse, (b)...

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Angular acceleration is defined as the rate of change in angular velocity with respect to time. It has both magnitude and direction. So, it is a vector quantity.

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Before diving into angular position, one should understand the basics of position and its importance along with usage in day-to-day life. When one talks of position, it’s always relative with respect to some other object. For example, position of earth with respect to sun, position of school with respect to house, etc. Angular position is the rotational analogue of linear position.

Question

Pulley
1 51°
72.5
35
kg
kg
Bench
Hs = 0.66
= 0.325
-Three objects are connected by weightless flexible strings as shown in the figure. The pulley has no appreciable mass or friction, and the string
connected to the block on the horizontal bench pulls on the block parallel to the bench surface. The coefficients of friction between the bench and the
block on it are u = 0.66 and Hx =0.325. You observe that this system remains at rest. Answer the following questions. Show all work. Clearly
indicate any fundamental principles used.
a. Draw a force diagram for the 35 kg block.
b. Draw a force diagram for the point connecting the three ropes.
c. Calculate the mass of block A.
d. Draw a force diagram for tlhe 72.5 kg block.
e. Calculate the friction force between the 72.5 kg block and the bench.

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A package is projected 10 m upward on a 15 ° inclined plane so that it reaches the top of the plane with zero velocity. Knowing that the coefficient of kinetic friction between the package and the incline is 0.15, determine the speed of the package when it returns to its original position.
GOAL Apply the concept of static friction to an object resting on an incline. PROBLEM Suppose a block with a mass of 2.50 kg is resting on a ramp. If the coefficient of static friction between the block and ramp is ng sin e 0.350, what maximum angle can the ramp make with the horizontal mg cos e e before the block starts to slip down? STRATEGY This is an application of Newton's second law involving an object in equilibrium. Choose tilted coordinates, as in the figure. Use the fact that the block is just about to slip when the force of static friction takes its maximum value, f. = 4n. SOLUTION Write Newton's laws for a static system (1) EF = mg sin e - u̟n = 0 in component form. The gravity force (2) EF = n - mg cos e = 0 has two components. Rearrange Equation (2) to get an n = mg cos 8 expression for the normal force n. Substitute the expression for n into EF, = mg sin 8 - H mgcos 0 = 0 → tan 8 =u. Equation (1) and solve for tan 0. Apply the inverse tangent function to get the answer.…
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