The code in the picture takes two sorted arrays of sizes m and n, then it merges and sorts them. Whats the best-case and worst-case for this alogrithm? 260 /*** This method handles joining and sorting two arrays@param nums1@param m@param nums2 - 2nd array@param n@return*/public static int[] mergeArr ( int nums1[], int m, int nums2[], int n){int i - 0,j = 0,k = 0;int arr[]2728first array- size of first array*293031size of 2nd array3233340353637new int[m+n]; //create a new array for merging%3!38while (i < m && j < n){//if the current term in in first array is less than 2ndif ( nums1[i] <= nums2[j]){arr[k++] = nums1[i++]; //add next term in nums1 to arr}else394041424344454647{4849arr[k++] = nums2[j++]; //add next term in nums2 to acr}}while (i < m){arr[k++]}while ( j

Worst Case: The size of array1 is 'm' and the size of array2 is 'n'. We are comparing elements of…

public static int[] mergeArr ( int nums1[], int m, int nums2[], int n) { int i - 0,j int arr[] 0,k - 0; - new int[m+n]; //create a new array for merging while (i < m && j < n) { //if the current term in in first array is less than 2nd if ( nums1[i] <- nums2[j]) { arr[k++] - nums1[i++]; //add next term in nums1 to acc } else { arr[k++] - nums2[j++]; //add next term in nums2 to acc while (i < m ) { arr[k++] } while ( j

public static int[] mergeArr ( int nums1[], int m, int nums2[], int n) { int i - 0,j int arr[] 0,k - 0; - new int[m+n]; //create a new array for merging while (i < m && j < n) { //if the current term in in first array is less than 2nd if ( nums1[i] <- nums2[j]) { arr[k++] - nums1[i++]; //add next term in nums1 to acc } else { arr[k++] - nums2[j++]; //add next term in nums2 to acc while (i < m ) { arr[k++] } while ( j

C++ for Engineers and Scientists

4th Edition

ISBN:9781133187844

Author:Bronson, Gary J.

Publisher:Bronson, Gary J.

Chapter7: Arrays

Section: Chapter Questions

Problem 1PP: (Statistics) a. Write a C++ program that reads a list of double-precision grades from the keyboard...

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