to.05 ,20 = 2.036 vP(t > 0.687) =0.25Suppose that random variable y? follows a chi-squared distribution with v = 5.E(x?) =and V(x?) =.10 vx*0.005,5 = 16.750P(x? > 6.626) =Suppose that the random variable F follows an F distribution with 20 numerator degrees of freedom and 24 denominator degrees of freedom.E(F) = 1.0909 ▼and V(F) =24Fo.05 ,20,24 = 2.027 v20Suppose instead thatfollows antion with degrees of freedom vị = 24 and v2 = 20. Without using the Distributions tool, what is the value0.3333of Fo.95,24,20?0.2499O 0.245O 0.432O 0.493O 0.266 Use the following Distributions tool to help you answer the following questions.t DistributionDegrees of Freedom = 15-5-4-3-2-112345AAtSuppose that random variable t follows a Student t distribution with degrees of freedom v = 20.E(t) is 0 v , and V(t) is 1.1111to.05 ,20 = 2.036P(t > 0.687) = 0.25Suppose that random variable x? follows a chi-squared distribution with v = 5.E(x?) =and V(x?) =x20.005 ,5 = 16.750P(x? > 6.626) =

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Description: to.05 ,20 = 2.036 vP(t > 0.687) =0.25Suppose that random variable y? follows a chi-squared distribution with v = 5.E(x?) =and V(x?) =.10 vx*0.005,5 = 16.750P(x? > 6.626) =Suppose that the random variable F follows an F distribution with 20 numerator

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P(t > 0.687) = 0.25 Suppose that random variable y? follows a chi-squared distribution with v = 5. E(x?) = , and V(x?) = 10 x0.005,s = 16.750 P(x? > 6.626) = Suppose that the random variable F follows an F distribution with 20 numerator degrees of freedom and 24 denominator degrees of freedom. E(F) = 1.0909 , and V(F) = 24 Fo.05 ,20,24 = 2.027 v 20 Suppose instead that F follows an tion with degrees of freedom VỊ = 24 and v2 = 20. Without using the Distributions tool, what is the value 0.3333 of Fo.95 ,24,20?

P(t > 0.687) = 0.25 Suppose that random variable y? follows a chi-squared distribution with v = 5. E(x?) = , and V(x?) = 10 x0.005,s = 16.750 P(x? > 6.626) = Suppose that the random variable F follows an F distribution with 20 numerator degrees of freedom and 24 denominator degrees of freedom. E(F) = 1.0909 , and V(F) = 24 Fo.05 ,20,24 = 2.027 v 20 Suppose instead that F follows an tion with degrees of freedom VỊ = 24 and v2 = 20. Without using the Distributions tool, what is the value 0.3333 of Fo.95 ,24,20?

MATLAB: An Introduction with Applications

6th Edition

ISBN:9781119256830

Author:Amos Gilat

Publisher:Amos Gilat

Chapter1: Starting With Matlab

Section: Chapter Questions

Problem 1P

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