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Ps RI 200 Rc ¹9₂ 28 о бог 1302 No₁ hfeq R₁ 12₂ Re = 1-2 ka RE=0.56 k 0.56 kn lg = 0.56 km = 1600 330 k = 110 kr

Ps RI 200 Rc ¹9₂ 28 о бог 1302 No₁ hfeq R₁ 12₂ Re = 1-2 ka RE=0.56 k 0.56 kn lg = 0.56 km = 1600 330 k = 110 kr

Introductory Circuit Analysis (13th Edition)
Introductory Circuit Analysis (13th Edition)
13th Edition
ISBN:9780133923605
Author:Robert L. Boylestad
Publisher:Robert L. Boylestad
Chapter1: Introduction
Section: Chapter Questions
Problem 1P: Visit your local library (at school or home) and describe the extent to which it provides literature...
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swer the ff: RI ds Rs 3. 201 Determine: a) Av₁ = V0₁/vi b) A√₂ = V0₂/Vi e) Zizo, = xo, RS $ 201 Rc LE IE2 xor 1302 hfey = 1600 R₁ 330 k = 12₂ = 110 kr Re = 1-2 ke RE= 0.56 k Si x' tor RL = 0.56 kn if RL is Connected acROSS RE = Voz 20₁ c) ANS = 2) A₁ = 10/₁ 102 No₁ Voz / Vs 0.56 kn 0.56 kn
Transcribed Image Text:swer the ff: RI ds Rs 3. 201 Determine: a) Av₁ = V0₁/vi b) A√₂ = V0₂/Vi e) Zizo, = xo, RS $ 201 Rc LE IE2 xor 1302 hfey = 1600 R₁ 330 k = 12₂ = 110 kr Re = 1-2 ke RE= 0.56 k Si x' tor RL = 0.56 kn if RL is Connected acROSS RE = Voz 20₁ c) ANS = 2) A₁ = 10/₁ 102 No₁ Voz / Vs 0.56 kn 0.56 kn
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