Provided here is a dataset from a class. This data was collected from an 8-10am course that met every Tuesday and Thursday.   Answer all of the following questions.  Give your answers in sentences and/or copy/paste your Excel graphs/commands when used.    2019 Data           Gender Age Height (in) Shoe Size Miles Home to school Classes this Semester M 20 77 15 3 4 F 45 63 11 8 3 F 20 62 8.5 22 4 F 19 68 9 7.5 4 M 19 70 9.5 6.5 4 F 18 63 6.5 6.5 5 F 21 62 5.5 2 4 F 19 65 7 7 4 F 18 64 8.5 5.5 5 F 19 60 7 15 3 F 21 60 6.5 5 1 M 19 72 11 15 5 M 42 68.75 11 5 1 M 18 74 11.5 2.5 4 F 18 62 6.5 7.5 4 F 19 60 7.5 3 5 F 20 59 4.5 3.5 5 M 20 78 14 87 5 M 19 72.5 12 0.5 4 M 21 66 8.5 5 4 M 19 76 12 45 5 M 19 71 12 22 5 M 19 69 11 4.5 4 F 19 65 7 2 4 F 25 66 8 1 2 M 19 68 10 5 4 M 19 72 11.5 82 4 F 18 64 8.5 21 4 F 23 70 9.5 4 3 D) Find the mean and standard deviation of the heights of this sample of students. E)  The Empirical Rule states that IF a data set is Normally distributed, that approximately 68% of the observations should fall within ONE standard deviation of the mean.  Typically, heights tend to be normally distributed.  IF this sample of student heights is normally distributed, give the lower and upper boundary of heights where approximately 68% of student heights should lie.  F)  Use simple probability (no technology needed) to find the probability that, if I chose a random student from this list, that student would be between these two boundary heights found in part E.  G)  What can you conclude about this specific sample of students' heights?  Do you believe that they are "normally distributed"?  Why/why not?

MATLAB: An Introduction with Applications
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ISBN:9781119256830
Author:Amos Gilat
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Chapter1: Starting With Matlab
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Provided here is a dataset from a class.

This data was collected from an 8-10am course that met every Tuesday and Thursday.   Answer all of the following questions.  Give your answers in sentences and/or copy/paste your Excel graphs/commands when used.   

2019 Data          
Gender Age Height (in) Shoe Size Miles Home to school Classes this Semester
M 20 77 15 3 4
F 45 63 11 8 3
F 20 62 8.5 22 4
F 19 68 9 7.5 4
M 19 70 9.5 6.5 4
F 18 63 6.5 6.5 5
F 21 62 5.5 2 4
F 19 65 7 7 4
F 18 64 8.5 5.5 5
F 19 60 7 15 3
F 21 60 6.5 5 1
M 19 72 11 15 5
M 42 68.75 11 5 1
M 18 74 11.5 2.5 4
F 18 62 6.5 7.5 4
F 19 60 7.5 3 5
F 20 59 4.5 3.5 5
M 20 78 14 87 5
M 19 72.5 12 0.5 4
M 21 66 8.5 5 4
M 19 76 12 45 5
M 19 71 12 22 5
M 19 69 11 4.5 4
F 19 65 7 2 4
F 25 66 8 1 2
M 19 68 10 5 4
M 19 72 11.5 82 4
F 18 64 8.5 21 4
F 23 70 9.5 4 3

D) Find the mean and standard deviation of the heights of this sample of students.

E)  The Empirical Rule states that IF a data set is Normally distributed, that approximately 68% of the observations should fall within ONE standard deviation of the mean.  Typically, heights tend to be normally distributed.  IF this sample of student heights is normally distributed, give the lower and upper boundary of heights where approximately 68% of student heights should lie. 

F)  Use simple probability (no technology needed) to find the probability that, if I chose a random student from this list, that student would be between these two boundary heights found in part E. 

G)  What can you conclude about this specific sample of students' heights?  Do you believe that they are "normally distributed"?  Why/why not?

### Summary Output of Regression Analysis

#### Regression Statistics
- **Multiple R:** 0.89325068
- **R Square:** 0.797896777
- **Adjusted R Square:** 0.790411473
- **Standard Error:** 2.477019721
- **Observations:** 29

#### ANOVA (Analysis of Variance)
- **Regression**
  - **df (Degrees of Freedom):** 1
  - **SS (Sum of Squares):** 654.0277343
  - **MS (Mean Square):** 654.0277343
  - **F (F-statistic):** 106.5950989
  - **Significance F:** 7.12498E-11

- **Residual**
  - **df (Degrees of Freedom):** 27
  - **SS (Sum of Squares):** 165.6619208
  - **MS (Mean Square):** 6.135626697

- **Total** 
  - **df (Degrees of Freedom):** 28
  - **SS (Sum of Squares):** 819.6896552

#### Coefficients
- **Intercept**
  - **Coefficient:** 49.5314004
  - **Standard Error:** 1.767067776
  - **t Stat (t-Statistic):** 28.0302776
  - **P-value:** 1.69215E-21
  - **Lower 95%:** 45.90567681
  - **Upper 95%:** 53.15712398
  - **Lower 95.0%:** 45.90567681
  - **Upper 95.0%:** 53.15712398

- **X Variable 1**
  - **Coefficient:** 1.891997735
  - **Standard Error:** 0.18325338
  - **t Stat (t-Statistic):** 10.32449025
  - **P-value:** 7.12498E-11
  - **Lower 95%:** 1.515992858
  - **Upper 95%:** 2.268002613
  - **Lower 95.0%:** 1.515992858
  - **Upper 95.0%:** 2
Transcribed Image Text:### Summary Output of Regression Analysis #### Regression Statistics - **Multiple R:** 0.89325068 - **R Square:** 0.797896777 - **Adjusted R Square:** 0.790411473 - **Standard Error:** 2.477019721 - **Observations:** 29 #### ANOVA (Analysis of Variance) - **Regression** - **df (Degrees of Freedom):** 1 - **SS (Sum of Squares):** 654.0277343 - **MS (Mean Square):** 654.0277343 - **F (F-statistic):** 106.5950989 - **Significance F:** 7.12498E-11 - **Residual** - **df (Degrees of Freedom):** 27 - **SS (Sum of Squares):** 165.6619208 - **MS (Mean Square):** 6.135626697 - **Total** - **df (Degrees of Freedom):** 28 - **SS (Sum of Squares):** 819.6896552 #### Coefficients - **Intercept** - **Coefficient:** 49.5314004 - **Standard Error:** 1.767067776 - **t Stat (t-Statistic):** 28.0302776 - **P-value:** 1.69215E-21 - **Lower 95%:** 45.90567681 - **Upper 95%:** 53.15712398 - **Lower 95.0%:** 45.90567681 - **Upper 95.0%:** 53.15712398 - **X Variable 1** - **Coefficient:** 1.891997735 - **Standard Error:** 0.18325338 - **t Stat (t-Statistic):** 10.32449025 - **P-value:** 7.12498E-11 - **Lower 95%:** 1.515992858 - **Upper 95%:** 2.268002613 - **Lower 95.0%:** 1.515992858 - **Upper 95.0%:** 2
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