Provided below are summary statistics for independent simple random samples from two populations. Use the pooled t-test and the pooledt-interval procedure to conduct the required hypothesis test and obtain the specified confidence interval.*= 21, s 4, n =11, x2 = 16, s2 =5, ng = 15a. Right-tailed test, a = 0.05b. 90% confidence interval......a. What are the correct hypotheses for a right-tailed test?OA Ho H42H =2OC. Ho HP2O B. Ho: H1 P2H 42OD. Ho: H

Answered: Image /qna-images/answer/418f49af-cd40-4f38-b7f5-61d92283d422.jpg

Answered: Provided below are summary statistics…

MATLAB: An Introduction with Applications

6th Edition

ISBN:9781119256830

Author:Amos Gilat

Publisher:Amos Gilat

Chapter1: Starting With Matlab

Section: Chapter Questions

Problem 1P

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The numbers of successes and the sample sizes for independent simple random samples from two populations are provided for a right-tailed test. Use a 90% confidence interval. Complete parts (a) through (d). X1 = 23, n, = 90, x2 = 18, n2 = 100, a = 0.05 Click here to view Click here to view table of areas under the standard normal curve for negative values of z. table of areas under the standard normal curve for positive values of z. a. Determine the sample proportions. Determine the sample proportion p P, = (Round to three decimal places as needed.)
For a one-tailed hypothesis test (upper tail) the p-value is computed to be 0.008. If the test is being conducted at 99% confidence, the null hypothesis could be rejected or not rejected depending on the sample size could be rejected or not rejected depending on the value of the mean of the sample is not rejected is rejected
What is the CI=confidence interval, OR = odds ratio, P value=probability of null value hypothesis for the following data tables. The data collected aims to show an association between people with diabetes and muscle loss.
3) A local municipality tests 25 samples of water and finds that the mean concentration of chlorine in the water is 150 mg/l with a standard deviation of 18 mg/l. Construct a 90% confidence interval for your results and draw the interval. Hypothesis Testing Test#- Claim# Vn %3D pq
Independent random samples are taken at a university to compare the average GPA of seniors to the average GPA of sophomores. Given a 90% confidence interval for the difference between the true average GPAs (seniors - sophomores) of (-0.05, 0.78), what can you conclude? Question 8 options: 1) There is no significant difference between the true average GPA for seniors and sophomores. 2) We do not have enough information to make a conclusion. 3) We are 90% confident that the average GPA of seniors is less than the average GPA of sophomores. 4) We are 90% confident that the average GPA of seniors is greater than the average GPA of sophomores. 5) We are 90% confident that the difference between the two sample GPAs falls within the interval.
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Two random samples are selected from two independent populations. A summary of the samples sizes and sample means is given below: n = 49, -56.4 ng - 40, 70.5 If the 93% confidence interval for the difference u - pgof the means is (-17.4129, -10.7871), what is the value of the pooled variance estimator? (You may assume equal population variances.) Pooled Variance Estimator =
In a random sample of males, it was found that 21 write with their left hands and 210 do not. In a random sample of females, it was found that 56 write with their left hands and 440 do not. Use a 0.05 significance level to test the claim that the rate of left-handedness among males is less than that among females. -Find the 90% confidence interval
The 95% confidence interval is (_,_)
help thank you!! A new method of HIV testing has been proposed based on a new quick detection procedure where saliva is examined. Suppose that the new method tests 176 HIV positive persons and falsely categorizes (i.e., return negative results) 25 of them. Assuming the current best standard of practice for saliva based quick detection HIV tests has a false negative rate of only 10%, determine if the accuracy of the two tests are significantly different at 95% confidence level. Assume that we can use a z-test. Let ?=False negative rate of new test What is the mean and standard deviation of the normal approximation for p-hat under Null hypothesis? answer choices
A data set includes data from student evaluations of courses. The summary statistics are n=82, x=4.85, s=0.72. Use a 0.10 significance level to test the claim that the population of student course evaluations has a mean equal to 5.00. Assume that a simple random sample has been selected. Identify the null and alternative hypotheses, test statistic, P-value.What are the null and alternative hypotheses?Determine the test statistic.(Round to two decimal places as needed.)Determine the P-value.
We randomly selected 29 TWU alum and asked them if they ever drink underage when in college? 12 said that they did. What is the 90% confidence interval for the true proportion of TWU alum who engaged in underaged drinking when in college? Enter your answers accurate to two decimal places but do not round until the end of the problem. The correct interpretation of the confidence interval is that we are 90% confident that the interval contains the Select an answer v of Select an answer v TWU alum who engaged in underaged drinking when in college. Can we conclude that the proportion of all TWU alum who engaged in underaged drinking when in college is less than 0.57? Justify your answer. Yes; the entire interval does not agree with this claim. O No; the entire interval agrees with this claim. O No; the entire interval does not agree with this claim. Yes; the entire interval agrees with this claim. Choose the best response that discusses the validity of your results. Questionable there is…

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