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Provide the correct exponents and distances to make the singularity function given valid for the beam shown. VI = 8 kN, V2 = 8 kN, V3 = 200 mm, and V4 = 1100 mm. Determine the reaction forces at the supports. AA va (mem) o The singularity functions are q = R1(x)ª – v1(x – P)4 – v2(x – Q)ª + R2(x – R)ª :-. :-. V = R1 – v1(x – D)“ – v2(x – E)* + R2(x – F)“ (1) M = R1x – v1(x - G)° – v2(x – H)C + R2(x – I)° (2) From the given singularity functions, the exponents are A = B= C= The distances P= mm Q = mm R= mm D= mm E= mm F= mm G= mm H= mm mm Reactions force R = |kN and reaction force R2 = |kN

Provide the correct exponents and distances to make the singularity function given valid for the beam shown. VI = 8 kN, V2 = 8 kN, V3 = 200 mm, and V4 = 1100 mm. Determine the reaction forces at the supports. AA va (mem) o The singularity functions are q = R1(x)ª – v1(x – P)4 – v2(x – Q)ª + R2(x – R)ª :-. :-. V = R1 – v1(x – D)“ – v2(x – E)* + R2(x – F)“ (1) M = R1x – v1(x - G)° – v2(x – H)C + R2(x – I)° (2) From the given singularity functions, the exponents are A = B= C= The distances P= mm Q = mm R= mm D= mm E= mm F= mm G= mm H= mm mm Reactions force R = |kN and reaction force R2 = |kN

Elements Of Electromagnetics
Elements Of Electromagnetics
7th Edition
ISBN:9780190698614
Author:Sadiku, Matthew N. O.
Publisher:Sadiku, Matthew N. O.
ChapterMA: Math Assessment
Section: Chapter Questions
Problem 1.1MA
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Provide the correct exponents and distances to make the singularity function given valid for the beam shown. VI = 8 kN, V2 = 8 kN, V3 = 200 mm, and V4 = 1100 mm. Determine the reaction forces at the supports. A v3 V37 (m) o The singularity functions are q = R1(x)ª – v1( – P)ª – v2(x – Q)ª + R2(x – R)ª - 2 - V = R1 – v1(x – D)B – v2(x – E)B + R2(x – F)® (1) M = R1x – v1(x – G)° – v2(x – H)° + R2(x – (2) From the given singularity functions, the exponents are A = B = C= The distances are P= mm Q = mm R= mm D= mm E= mm F= mm G= mm H= mm mm Reactions force R = kN and reaction force R2 = kN
Transcribed Image Text:Provide the correct exponents and distances to make the singularity function given valid for the beam shown. VI = 8 kN, V2 = 8 kN, V3 = 200 mm, and V4 = 1100 mm. Determine the reaction forces at the supports. A v3 V37 (m) o The singularity functions are q = R1(x)ª – v1( – P)ª – v2(x – Q)ª + R2(x – R)ª - 2 - V = R1 – v1(x – D)B – v2(x – E)B + R2(x – F)® (1) M = R1x – v1(x – G)° – v2(x – H)° + R2(x – (2) From the given singularity functions, the exponents are A = B = C= The distances are P= mm Q = mm R= mm D= mm E= mm F= mm G= mm H= mm mm Reactions force R = kN and reaction force R2 = kN
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