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Provide a complete curved-arrow mechanism for this transformation

Provide a complete curved-arrow mechanism for this transformation

Chemistry
Chemistry
10th Edition
ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Chapter1: Chemical Foundations
Section: Chapter Questions
Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
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Provide a complete curved-arrow mechanism for this transformation. I am confused.

This image depicts a chemical reaction sequence involving two main steps: 1. **First Reaction Step**: - Starting with ethyl acetoacetate (ethyl 3-oxobutanoate), the compound undergoes a reaction with sodium ethoxide (NaOEt) in ethanol (EtOH). - A phenyl derivative (bromobenzene, Br with a phenyl ring) is then added in one equivalent to the reaction. - This results in the substitution of the ethyl acetoacetate, forming a new compound featuring an added phenyl group. 2. **Second Reaction Step**: - The synthesized compound is treated with sodium hydroxide (NaOH) in water (H₂O). - Hydrochloric acid (HCl) is then introduced, with the reaction taking place under heat (represented by the delta symbol, Δ). - This leads to the decarboxylation of the compound, producing a ketone with a phenyl group and a methyl branching chain. The sequence captures a classic synthetic route often utilized in organic chemistry to construct more complex molecules from simpler starting components.
Transcribed Image Text:This image depicts a chemical reaction sequence involving two main steps: 1. **First Reaction Step**: - Starting with ethyl acetoacetate (ethyl 3-oxobutanoate), the compound undergoes a reaction with sodium ethoxide (NaOEt) in ethanol (EtOH). - A phenyl derivative (bromobenzene, Br with a phenyl ring) is then added in one equivalent to the reaction. - This results in the substitution of the ethyl acetoacetate, forming a new compound featuring an added phenyl group. 2. **Second Reaction Step**: - The synthesized compound is treated with sodium hydroxide (NaOH) in water (H₂O). - Hydrochloric acid (HCl) is then introduced, with the reaction taking place under heat (represented by the delta symbol, Δ). - This leads to the decarboxylation of the compound, producing a ketone with a phenyl group and a methyl branching chain. The sequence captures a classic synthetic route often utilized in organic chemistry to construct more complex molecules from simpler starting components.
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