Providde a 95% conffidence interrval esstimate for the true averrage call durration. Hinnt: Use poppulation std instead of sammple std whenever poppulation std is given. That is to use σ=2 instead of s = 2.37901. A. 6.1478 ± 1.645 × 2.37901 / √100 B. 6.1478 ± 2 C.6.1478 ± 1.96 × 2.37901 / √100 D. 6.1478 ± 1.645 × 2 / √100 E. 6.1478 ± 1.96 × 2 / √100 We colllected a sammple of 100 telepphone callls. If we waant to cutt the margin of error in half (meaning that we wantt to redduce the margin of errror to 50% of yourr answer in Part 3), how largge of sammple is needed? Assume a 90% confidence level. A. n = (1.96 × 2 / 0.329)^2 B. n = (1.96 × 2 / 0.1645)^2 C. n = (1.645 × 2 / 0.329)^2 E. n = (1.645 × 2 / 0.1645)^2
Providde a 95% conffidence interrval esstimate for the true averrage call durration. Hinnt: Use poppulation std instead of sammple std whenever poppulation std is given. That is to use σ=2 instead of s = 2.37901. A. 6.1478 ± 1.645 × 2.37901 / √100 B. 6.1478 ± 2 C.6.1478 ± 1.96 × 2.37901 / √100 D. 6.1478 ± 1.645 × 2 / √100 E. 6.1478 ± 1.96 × 2 / √100 We colllected a sammple of 100 telepphone callls. If we waant to cutt the margin of error in half (meaning that we wantt to redduce the margin of errror to 50% of yourr answer in Part 3), how largge of sammple is needed? Assume a 90% confidence level. A. n = (1.96 × 2 / 0.329)^2 B. n = (1.96 × 2 / 0.1645)^2 C. n = (1.645 × 2 / 0.329)^2 E. n = (1.645 × 2 / 0.1645)^2
MATLAB: An Introduction with Applications
6th Edition
ISBN:9781119256830
Author:Amos Gilat
Publisher:Amos Gilat
Chapter1: Starting With Matlab
Section: Chapter Questions
Problem 1P
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Providde a 95% conffidence interrval esstimate for the true averrage call durration. Hinnt: Use poppulation std instead of sammple std whenever poppulation std is given. That is to use σ=2 instead of s = 2.37901.
A. 6.1478 ± 1.645 × 2.37901 / √100
B. 6.1478 ± 2
C.6.1478 ± 1.96 × 2.37901 / √100
D. 6.1478 ± 1.645 × 2 / √100
E. 6.1478 ± 1.96 × 2 / √100
We colllected a sammple of 100 telepphone callls. If we waant to cutt the margin of error in half (meaning that we wantt to redduce the margin of errror to 50% of yourr answer in Part 3), how largge of sammple is needed? Assume a 90% confidence level.
A. n = (1.96 × 2 / 0.329)^2
B. n = (1.96 × 2 / 0.1645)^2
C. n = (1.645 × 2 / 0.329)^2
E. n = (1.645 × 2 / 0.1645)^2
Transcribed Image Text:Summary Statistics for Duration
Count
Average
Median
Mode
Variance
Standard deviation 2.37901
Minimum
Maximum
Range
Lower quartile
Upper quartile
Interquartile range 3.235
100
6.1478
6.085
5.65968
|-1.48
10.7
12.18
4.805
8.04
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