Prove using Mathematical Induction that: The sum of the squares of the first n positive integers is equal to n(n+1}{2n+1)/6: 1²+2²+3²+...+n² = n(n+1)(2n+1)
Prove using Mathematical Induction that: The sum of the squares of the first n positive integers is equal to n(n+1}{2n+1)/6: 1²+2²+3²+...+n² = n(n+1)(2n+1)
Advanced Engineering Mathematics
10th Edition
ISBN:9780470458365
Author:Erwin Kreyszig
Publisher:Erwin Kreyszig
Chapter2: Second-order Linear Odes
Section: Chapter Questions
Problem 1RQ
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Transcribed Image Text:Prove using Mathematical Induction that:
The sum of the squares of the first n positive integers is equal to n(n+1}{2n+1)/6:
1²+2²+3²+...+n² =
n(n+1)(2n+1)
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