Prove the statement using the , & definition of a limit. 6 + 4x lim x 1 = 2 Given & > 0, we need ---Select--- choose 8 = ---Select--- · then 0 6 + 4x ---Select--- ✓ But 6 + 4x 5 5 <&. Thus, lim (6+4x) = 2 by the definition of a limit. such that if 0 < |x-1| < 6, then > | ( 6 + 4x) - 2 | < |x-1| < 8⇒ |54|
Prove the statement using the , & definition of a limit. 6 + 4x lim x 1 = 2 Given & > 0, we need ---Select--- choose 8 = ---Select--- · then 0 6 + 4x ---Select--- ✓ But 6 + 4x 5 5 <&. Thus, lim (6+4x) = 2 by the definition of a limit. such that if 0 < |x-1| < 6, then > | ( 6 + 4x) - 2 | < |x-1| < 8⇒ |54|
Calculus: Early Transcendentals
8th Edition
ISBN:9781285741550
Author:James Stewart
Publisher:James Stewart
Chapter1: Functions And Models
Section: Chapter Questions
Problem 1RCC: (a) What is a function? What are its domain and range? (b) What is the graph of a function? (c) How...
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