Prove the statement by mathematical induction. 3+5+7+…+(2n+1)=n(n+2) 1. Proposition is true when n=1, since n(n+2)=A(1+2)=B. A= B= 2. We will assume that the proposition is true for a constant k=n, so 3+5+7+…+(2k+1)=C(k+D). C= D= 3. Then, 3+5+7+…+(2k+1)+(Ek+F)=k(k+2)+(Gk+H). E= F= G= H= 4. Thus: ∑i=1k+12k+1=k2+4k+3

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