Prove the identity sin(7 – 0) = sin 0. %3D

Q: (a) Evaluate| cos (4x) -dx. (1+ 2sin ( n(4x)*

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Q: sinx = 5/13, x E 5,1], then cosx =?

A: We are solving the problem by the property of trigonometry ratio.

Q: Convert to cartesian Sin ()+ tan (0) %3D

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Q: Differentiate.

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Q: Determine the amplitude of the sinusoidal function - 4 sin 3(x - ) +2 y = Your answer

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Q: 5 sin x +3= -0.8

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Q: sin 2x V2 – cos 2x dx

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Q: 77/4 tan d:

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Q: Differentiate.

A: Consider the provided function, y=cosetan3x Differentiate the provided function with respect to x.

Q: 3 + cos 3x dx Evaluate sin 3x

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Q: Show that tan-1 ( 1/v ) = π/2 - tan-1 v, if v > 0.

A: To prove tan-11v=π2-tan-1v, let  x=tan-1v then tan x=v1tan x=1v Since  tanx=1cotxcotx=1v ⋯ (1)

Q: 1 cose sin 0 2/3 2 csce: 3

A: Explanation and solutions is given below....

Q: sin 2x cos 3х dx

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Q: SOLVE FOR X y = 1 + sin (7)

A: Solve equation for x

Q: sec2 (0) – 1 sec2 (0) sin?(8) %|

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Q: sin-1 (-금).

A: Explanation of the solution is given below...

Q: Si cos°(3x)sin (3x) – cos (3x) sin°(3x) dx

A: First we common out cos7(3x) sin7(3x) and then apply the formula cos2(3x)-sin2(3x)=cos(6x)

Q: sin(3r) dr.

A: Given integral is,

Q: Evaluate [ sin” (tanx) x² I= So dx

A: Given, Integral  And according to lobachevsky integral formula

Q: sin -1(-i) =

A:

Q: A normal distribution of scores has a standard deviation of 10. Find the z-scores corresponding to…

A: We have given standard deviation as σ = 10.

Q: L{4 sin 5t + 7 cos 6t}

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Q: 3 cos xdx 1-sinx

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Q: 1– sin 2x

A: We have given (sin x – cos x)2 = 1 – sin 2x