Prove the following using mathematical induction. 1. 1 + 2' + 3' + ... + n = n'(n + 1)2 4 2.

Algebra & Trigonometry with Analytic Geometry
13th Edition
ISBN:9781133382119
Author:Swokowski
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Chapter10: Sequences, Series, And Probability
Section10.4: Mathematical Induction
Problem 27E
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Prove the following using mathematical induction.
1.
M
13 + 23 + 33 + ... +n' = n°(n + 1)2
4
2.
1.2+2 3+3 4+... + n(n + 1) =
n(n +1)(n+ 2) for any neN
3.
3
2 + 22 + 23 +... + 2" = 2n*1 – 2, for any n eN
4.
5.
1+8+ 16 +... + 8(n – 1) = (2n – 1)2, for any n e N
n(n +3)
6. 1.2.3*2-3-4* 3.4-5** n(n + 1)(n + 2) 4(n + 1)(n + 2)
1
for any neN
...
7.
n? > 2n, for any positive integer n23
8.
3"- 2 2 10n, for any positive integer n 2 4
9.
4° -1 is divisible by 3 for any neN
TA BA
foome
10.
n° + 3n? + 2n is divisible by 6 for any n e N
Transcribed Image Text:Prove the following using mathematical induction. 1. M 13 + 23 + 33 + ... +n' = n°(n + 1)2 4 2. 1.2+2 3+3 4+... + n(n + 1) = n(n +1)(n+ 2) for any neN 3. 3 2 + 22 + 23 +... + 2" = 2n*1 – 2, for any n eN 4. 5. 1+8+ 16 +... + 8(n – 1) = (2n – 1)2, for any n e N n(n +3) 6. 1.2.3*2-3-4* 3.4-5** n(n + 1)(n + 2) 4(n + 1)(n + 2) 1 for any neN ... 7. n? > 2n, for any positive integer n23 8. 3"- 2 2 10n, for any positive integer n 2 4 9. 4° -1 is divisible by 3 for any neN TA BA foome 10. n° + 3n? + 2n is divisible by 6 for any n e N
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