Prove the following statement directly from the definitions. The product of any two even integers is a multiple of 4. vr such that m =---Select--- v, and there exists ---Select-- Proof: Let m and n be any two even integers. By definition of even there exists ---Select--- such that n = ---Select- v By substitution, mn = 4 - which is an integer because --Select--- v of integers are integers. Thus mn = 4- (an integer), and so 4|mn by definition of divisibility.
Prove the following statement directly from the definitions. The product of any two even integers is a multiple of 4. vr such that m =---Select--- v, and there exists ---Select-- Proof: Let m and n be any two even integers. By definition of even there exists ---Select--- such that n = ---Select- v By substitution, mn = 4 - which is an integer because --Select--- v of integers are integers. Thus mn = 4- (an integer), and so 4|mn by definition of divisibility.
Calculus: Early Transcendentals
8th Edition
ISBN:9781285741550
Author:James Stewart
Publisher:James Stewart
Chapter1: Functions And Models
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Problem 1RCC: (a) What is a function? What are its domain and range? (b) What is the graph of a function? (c) How...
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Transcribed Image Text:Prove the following statement directly from the definitions.
The product of any two even integers is a multiple of 4.
vs
Proof: Let m and n be any two even integers. By definition of even there exists ---Select--
such that n = ---Select--- v
v r such that m = ---Select--- v, and there exists --Select---
By substitution, mn = 4
which is an integer because ---Select--- v of integers are integers.
Thus mn = 4 (an integer), and so 4|mn by definition of divisibility.
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