Prove that triangle APC is similar to triangle BPD. BQuestion 6Suppose that a light source at A is above a reflective surface ST, and thereflected light is observed at B. Further suppose that at the point ofreflection P, the angle of incidence is (90° – a) and the angle of reflectionT.is (90°- B). This means that ZAPS= a and ZBPT = B. Let the image ofA in the reflecting surface be at A' and let A'A intersect ST at C. It isassumed that light travels in a straight line and therefore A'PB is a straightline, and that reflection does not alter the distance, i.e. AC= A'C.CP%DA'

Concept: Similar triangles: Triangles that are similar in shape but differ in size are known as…

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Elementary Geometry For College Students, 7e

7th Edition

ISBN:9781337614085

Author:Alexander, Daniel C.; Koeberlein, Geralyn M.

Publisher:Alexander, Daniel C.; Koeberlein, Geralyn M.

ChapterP: Preliminary Concepts

SectionP.CT: Test

Problem 1CT

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Prove that triangle APC is similar to triangle BPD.

Polygon with three sides, three angles, and three vertices. Based on the properties of each side, the types of triangles are scalene (triangle with three three different lengths and three different angles), isosceles (angle with two equal sides and two equal angles), and equilateral (three equal sides and three angles of 60°). The types of angles are acute (less than 90°); obtuse (greater than 90°); and right (90°).

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