Prove that the square root of 8 is irrational

Computer Networking: A Top-Down Approach (7th Edition)
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ISBN:9780133594140
Author:James Kurose, Keith Ross
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Prove that the square root of 8 is irrational

Expert Solution
Step 1

The proof is as following:

Proof:

Let us consider that √8 = a/b which means it is a rational number with integers a, b
and gcd(a,b) = 1 that means its ratio is simplified.

which means that: 8 = a²/b²
=> 8b² = a²


It shows that a² is divisible by 8 as well as which shows 8 divides a.

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