Prove that the mean and variance of a binomially distributed random variable are respectively µ=np and o2=np(1-p)

A First Course in Probability (10th Edition)
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Chapter1: Combinatorial Analysis
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Prove that the mean and variance of a binomially distributed random variable are respectively    ?=?? ??? ?2=??(1−?)

 

Prove that the mean and variance of a binomially distributed random variable are respectively \( \mu = np \) and \( \sigma^2 = np(1-p) \). 

In this statement, \( n \) represents the number of trials, \( p \) is the probability of success in each trial, \( \mu \) denotes the mean, and \( \sigma^2 \) denotes the variance of the binomial distribution.
Transcribed Image Text:Prove that the mean and variance of a binomially distributed random variable are respectively \( \mu = np \) and \( \sigma^2 = np(1-p) \). In this statement, \( n \) represents the number of trials, \( p \) is the probability of success in each trial, \( \mu \) denotes the mean, and \( \sigma^2 \) denotes the variance of the binomial distribution.
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