Prove that the following equation is an identity. csc x-sin x cot x Choose the correct answer below. O A. O B. O C. = COS X O D. csc x- sin x 1- cos x cot x sin x csc x- sin x cot x csc x- sin x cot x csc x- sin x cot x 2 1- cos X sin x 2 1 - sinx COS X 2 1- sin x COS X 2 COS X COS X 2 sin x sin x 2 COS X COS X 2 sinx sin x = cos X = cos X = cos X = cos x
Prove that the following equation is an identity. csc x-sin x cot x Choose the correct answer below. O A. O B. O C. = COS X O D. csc x- sin x 1- cos x cot x sin x csc x- sin x cot x csc x- sin x cot x csc x- sin x cot x 2 1- cos X sin x 2 1 - sinx COS X 2 1- sin x COS X 2 COS X COS X 2 sin x sin x 2 COS X COS X 2 sinx sin x = cos X = cos X = cos X = cos x
Trigonometry (11th Edition)
11th Edition
ISBN:9780134217437
Author:Margaret L. Lial, John Hornsby, David I. Schneider, Callie Daniels
Publisher:Margaret L. Lial, John Hornsby, David I. Schneider, Callie Daniels
Chapter1: Trigonometric Functions
Section: Chapter Questions
Problem 1RE:
1. Give the measures of the complement and the supplement of an angle measuring 35°.
Related questions
Question
![**Problem Statement:**
Prove that the following equation is an identity.
\[
\frac{\text{csc } x - \sin x}{\cot x} = \cos x
\]
**Multiple Choice Question:**
Choose the correct answer below.
**Option A:**
\[
\frac{\text{csc } x - \sin x}{\cot x} = \frac{1 - \cos^2 x}{\sin x} \times \frac{\cos^2 x}{\cos x} = \cos x
\]
**Option B:**
\[
\frac{\text{csc } x - \sin x}{\cot x} = \frac{1 - \cos^2 x}{\sin x} \times \frac{\sin^2 x}{\sin x} = \cos x
\]
**Option C:**
\[
\frac{\text{csc } x - \sin x}{\cot x} = \frac{1 - \sin^2 x}{\cos x} \times \frac{\cos^2 x}{\cos x} = \cos x
\]
**Option D:**
\[
\frac{\text{csc } x - \sin x}{\cot x} = \frac{1 - \sin^2 x}{\cos x} \times \frac{\sin^2 x}{\sin x} = \cos x
\]](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F2c0ab83b-f0ee-42a8-ae12-58396f46c55e%2Fdde445e4-dd3b-4552-88aa-55c299fac7da%2Fbbvakpx_processed.png&w=3840&q=75)
Transcribed Image Text:**Problem Statement:**
Prove that the following equation is an identity.
\[
\frac{\text{csc } x - \sin x}{\cot x} = \cos x
\]
**Multiple Choice Question:**
Choose the correct answer below.
**Option A:**
\[
\frac{\text{csc } x - \sin x}{\cot x} = \frac{1 - \cos^2 x}{\sin x} \times \frac{\cos^2 x}{\cos x} = \cos x
\]
**Option B:**
\[
\frac{\text{csc } x - \sin x}{\cot x} = \frac{1 - \cos^2 x}{\sin x} \times \frac{\sin^2 x}{\sin x} = \cos x
\]
**Option C:**
\[
\frac{\text{csc } x - \sin x}{\cot x} = \frac{1 - \sin^2 x}{\cos x} \times \frac{\cos^2 x}{\cos x} = \cos x
\]
**Option D:**
\[
\frac{\text{csc } x - \sin x}{\cot x} = \frac{1 - \sin^2 x}{\cos x} \times \frac{\sin^2 x}{\sin x} = \cos x
\]
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