Prove that the area of a square whose diagonal has length d is A = A = 1/2d². A square with a diagonal of length d is given. The area of the square is A = -d₁ - d₂ with diagonal lengths d and d₂ because a square has ---Select--- ]. It follows that d₁ = d₂ because a square has ---Select--- . So, given one diagonal of length d, the other diagonal has length 1) A = = 1/8². . Therefore by Substitution, the area is
Prove that the area of a square whose diagonal has length d is A = A = 1/2d². A square with a diagonal of length d is given. The area of the square is A = -d₁ - d₂ with diagonal lengths d and d₂ because a square has ---Select--- ]. It follows that d₁ = d₂ because a square has ---Select--- . So, given one diagonal of length d, the other diagonal has length 1) A = = 1/8². . Therefore by Substitution, the area is
Elementary Geometry For College Students, 7e
7th Edition
ISBN:9781337614085
Author:Alexander, Daniel C.; Koeberlein, Geralyn M.
Publisher:Alexander, Daniel C.; Koeberlein, Geralyn M.
ChapterP: Preliminary Concepts
SectionP.CT: Test
Problem 1CT
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![Prove that the area of a square whose diagonal has length d is A = d².
A square with a diagonal of length d is given. The area of the square is A =
because a square has |---Select---
diagonal of length d, the other diagonal has length
]) = 1/20².
A = 1/2d²
d.
(1
=d₁d₂ with diagonal lengths d and d
. It follows that d₁ = d₂ because a square has ---Select---
Therefore by Substitution, the area is
So, given one](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F5c33053e-aa43-49cf-b2bb-78272e2ba689%2Fc3445cf8-b660-4c85-ba7f-294abde0d680%2F8rpglis_processed.png&w=3840&q=75)
Transcribed Image Text:Prove that the area of a square whose diagonal has length d is A = d².
A square with a diagonal of length d is given. The area of the square is A =
because a square has |---Select---
diagonal of length d, the other diagonal has length
]) = 1/20².
A = 1/2d²
d.
(1
=d₁d₂ with diagonal lengths d and d
. It follows that d₁ = d₂ because a square has ---Select---
Therefore by Substitution, the area is
So, given one
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