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Prove that the area of a square whose diagonal has length d is A = A = 1/2d². A square with a diagonal of length d is given. The area of the square is A = -d₁ - d₂ with diagonal lengths d and d₂ because a square has ---Select--- ]. It follows that d₁ = d₂ because a square has ---Select--- . So, given one diagonal of length d, the other diagonal has length 1) A = = 1/8². . Therefore by Substitution, the area is

Prove that the area of a square whose diagonal has length d is A = A = 1/2d². A square with a diagonal of length d is given. The area of the square is A = -d₁ - d₂ with diagonal lengths d and d₂ because a square has ---Select--- ]. It follows that d₁ = d₂ because a square has ---Select--- . So, given one diagonal of length d, the other diagonal has length 1) A = = 1/8². . Therefore by Substitution, the area is

Elementary Geometry For College Students, 7e
Elementary Geometry For College Students, 7e
7th Edition
ISBN:9781337614085
Author:Alexander, Daniel C.; Koeberlein, Geralyn M.
Publisher:Alexander, Daniel C.; Koeberlein, Geralyn M.
ChapterP: Preliminary Concepts
SectionP.CT: Test
Problem 1CT
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Prove that the area of a square whose diagonal has length d is A = d². A square with a diagonal of length d is given. The area of the square is A = because a square has |---Select--- diagonal of length d, the other diagonal has length ]) = 1/20². A = 1/2d² d. (1 =d₁d₂ with diagonal lengths d and d . It follows that d₁ = d₂ because a square has ---Select--- Therefore by Substitution, the area is So, given one
Transcribed Image Text:Prove that the area of a square whose diagonal has length d is A = d². A square with a diagonal of length d is given. The area of the square is A = because a square has |---Select--- diagonal of length d, the other diagonal has length ]) = 1/20². A = 1/2d² d. (1 =d₁d₂ with diagonal lengths d and d . It follows that d₁ = d₂ because a square has ---Select--- Therefore by Substitution, the area is So, given one
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