Prove that the algorithm takes (o(n) running time to compute this task. Please formulate the summation equation for this proof and explain but please use the summation equation symbol. I am a bit confused.
Prove that the algorithm takes (o(n) running time to compute this task. Please formulate the summation equation for this proof and explain but please use the summation equation symbol. I am a bit confused.
Database System Concepts
7th Edition
ISBN:9780078022159
Author:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan
Publisher:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan
Chapter1: Introduction
Section: Chapter Questions
Problem 1PE
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Prove that the
summation equation for this proof and explain but please use the summation equation symbol. I am a bit confused.
![import java.util.*;
public class Main {
}
public static void main(String[] args) {
int[] arr = {16, 17, 4, 3, 5, 2};
List<Integer> dominantElements = findDominantElements (arr);
System.out.println("Dominant elements in the array: + dominantElements);
}
1 usage
public static List<Integer> findDominantElements (int[] arr) {
List<Integer> result = new ArrayList<>();
int maxSoFar = arr[arr.length - 1];
}
result.add(maxSoFar);
for (int i = arr.length 2; i >= 0; i--) {
if (arr[i] > maxSoFar) {
maxSoFar = arr[i];
result.add(maxSoFar);
}
}
Collections.reverse(result);
return result;](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F9b63d5f0-a313-4df7-92fd-2acb696a8a17%2F73b05f21-8911-4c46-9b3d-09a781756233%2Ftg7fd7m_processed.png&w=3840&q=75)
Transcribed Image Text:import java.util.*;
public class Main {
}
public static void main(String[] args) {
int[] arr = {16, 17, 4, 3, 5, 2};
List<Integer> dominantElements = findDominantElements (arr);
System.out.println("Dominant elements in the array: + dominantElements);
}
1 usage
public static List<Integer> findDominantElements (int[] arr) {
List<Integer> result = new ArrayList<>();
int maxSoFar = arr[arr.length - 1];
}
result.add(maxSoFar);
for (int i = arr.length 2; i >= 0; i--) {
if (arr[i] > maxSoFar) {
maxSoFar = arr[i];
result.add(maxSoFar);
}
}
Collections.reverse(result);
return result;
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