Prove that in Euclidean geometry (so using the 5th postulate) the sum of the angles in a triangle is equal to a straight angle. (For convenience you can use 180° as the measure of a straight angle. As we discussed in class you cannot assume that there is a single, consistent measure for the sum of the angles.)
Prove that in Euclidean geometry (so using the 5th postulate) the sum of the angles in a triangle is equal to a straight angle. (For convenience you can use 180° as the measure of a straight angle. As we discussed in class you cannot assume that there is a single, consistent measure for the sum of the angles.)
Elementary Geometry For College Students, 7e
7th Edition
ISBN:9781337614085
Author:Alexander, Daniel C.; Koeberlein, Geralyn M.
Publisher:Alexander, Daniel C.; Koeberlein, Geralyn M.
ChapterP: Preliminary Concepts
SectionP.CT: Test
Problem 1CT
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![Prove that in Euclidean geometry (so using the 5th postulate) the sum of
the angles in a triangle is equal to a straight angle. (For convenience you
can use 180° as the measure of a straight angle. As we discussed in class
you cannot assume that there is a single, consistent measure for the
sum of the angles.)
Please try to figure this out rather than looking up a proof online
(though you're welcome to do that afterwards; there are many).
If you get stuck you may want to use the proof above and the diagram
below in which lines AB and CD are parallel:
E
e
B
LL
G](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F67a1c206-9795-4fe0-8bb2-ac1243811732%2F139b1f4a-e788-4bc6-875b-27cf4b138542%2Fe3jwlmd_processed.png&w=3840&q=75)
Transcribed Image Text:Prove that in Euclidean geometry (so using the 5th postulate) the sum of
the angles in a triangle is equal to a straight angle. (For convenience you
can use 180° as the measure of a straight angle. As we discussed in class
you cannot assume that there is a single, consistent measure for the
sum of the angles.)
Please try to figure this out rather than looking up a proof online
(though you're welcome to do that afterwards; there are many).
If you get stuck you may want to use the proof above and the diagram
below in which lines AB and CD are parallel:
E
e
B
LL
G
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