Prove that for the general equation of degree 2 Ax² + Bxy + Cy² + Dx + Ey+F = 0 that the angle of rotation 0 need to remove the cross product term in a coordinate transformation is given by A-C cot 20 B

Algebra & Trigonometry with Analytic Geometry
13th Edition
ISBN:9781133382119
Author:Swokowski
Publisher:Swokowski
Chapter11: Topics From Analytic Geometry
Section11.1: Parabolas
Problem 24E
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**Title: Proving the Rotation Angle to Remove the Cross Product Term in a General Equation of Degree 2**

**Objective:** To demonstrate that for the general equation of degree 2:

\[ Ax^2 + Bxy + Cy^2 + Dx + Ey + F = 0 \]

the angle of rotation (θ) needed to remove the cross product term (Bxy) in a coordinate transformation is given by the expression:

\[ \cot 2θ = \frac{A - C}{B} \]

**Detailed Explanation:**

To eliminate the cross product term in the quadratic equation, we need to determine the angle θ that will convert the original coordinate system (x, y) to a new coordinate system (x', y') where the cross product term vanishes.

### Step-by-Step Proof:

1. **Original Coordinate System:**
   Consider the general quadratic equation:
   \[
   Ax^2 + Bxy + Cy^2 + Dx + Ey + F = 0
   \]

2. **New Coordinate System After Rotation:**
   When the coordinate system is rotated by an angle θ, the new coordinates (x', y') can be expressed in terms of the original coordinates (x, y) as:
   \[
   x' = x \cos θ + y \sin θ
   \]
   \[
   y' = -x \sin θ + y \cos θ
   \]

3. **Substitute New Coordinates Into the Original Equation:**
   Express the original equation in terms of x' and y'. Upon substitution, terms involving \( x'y' \) arise, representing the mixed product term. Our goal is to find θ such that the coefficient of \( x'y' \) becomes zero.

4. **Coefficient of \( x'y' \):**
   The coefficient of \( x'y' \) after substitution is computed by focusing on the mixed terms generated by the transformation. This coefficient can be shown as a function of cosine and sine terms, leading to the equation involving cotangent (cot).

5. **Condition for Removing the Cross Product Term:**
   For the coefficient of \( x'y' \) to be zero, we obtain the condition:
   \[
   \cot 2θ = \frac{A - C}{B}
   \]

This completes the proof that the angle θ needed to remove the cross product term is given by the above equation. By rotating the coordinate
Transcribed Image Text:**Title: Proving the Rotation Angle to Remove the Cross Product Term in a General Equation of Degree 2** **Objective:** To demonstrate that for the general equation of degree 2: \[ Ax^2 + Bxy + Cy^2 + Dx + Ey + F = 0 \] the angle of rotation (θ) needed to remove the cross product term (Bxy) in a coordinate transformation is given by the expression: \[ \cot 2θ = \frac{A - C}{B} \] **Detailed Explanation:** To eliminate the cross product term in the quadratic equation, we need to determine the angle θ that will convert the original coordinate system (x, y) to a new coordinate system (x', y') where the cross product term vanishes. ### Step-by-Step Proof: 1. **Original Coordinate System:** Consider the general quadratic equation: \[ Ax^2 + Bxy + Cy^2 + Dx + Ey + F = 0 \] 2. **New Coordinate System After Rotation:** When the coordinate system is rotated by an angle θ, the new coordinates (x', y') can be expressed in terms of the original coordinates (x, y) as: \[ x' = x \cos θ + y \sin θ \] \[ y' = -x \sin θ + y \cos θ \] 3. **Substitute New Coordinates Into the Original Equation:** Express the original equation in terms of x' and y'. Upon substitution, terms involving \( x'y' \) arise, representing the mixed product term. Our goal is to find θ such that the coefficient of \( x'y' \) becomes zero. 4. **Coefficient of \( x'y' \):** The coefficient of \( x'y' \) after substitution is computed by focusing on the mixed terms generated by the transformation. This coefficient can be shown as a function of cosine and sine terms, leading to the equation involving cotangent (cot). 5. **Condition for Removing the Cross Product Term:** For the coefficient of \( x'y' \) to be zero, we obtain the condition: \[ \cot 2θ = \frac{A - C}{B} \] This completes the proof that the angle θ needed to remove the cross product term is given by the above equation. By rotating the coordinate
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