Prove that for all integers x, if x is not divisible by 7, then x^3 ≡ 1 mod 7 or x^3 ≡ −1 mod 7.

Advanced Engineering Mathematics
10th Edition
ISBN:9780470458365
Author:Erwin Kreyszig
Publisher:Erwin Kreyszig
Chapter2: Second-order Linear Odes
Section: Chapter Questions
Problem 1RQ
icon
Related questions
Question

1. Show, using modular arithmetic, that for all n ∈ N, 3(7^3n) + 2^n+3 is divisible by 11.


2. Prove that for all integers x,
if x is not divisible by 7, then x^3 ≡ 1 mod 7 or x^3 ≡ −1 mod 7.
Hint: There are 6 cases to consider.


3. Prove or disprove each of the following two statements.
(i) For all integers x and y and natural numbers n,
if xy ≡ 0 mod n, then x ≡ 0 mod n or y ≡ 0 mod n.


(ii) For all natural numbers n > 4 and integers x, if x^2 ≡ 4 mod n, then x ≡ 2 mod n.


4. Fermat’s Little Theorem says that for all natural numbers p and integers x, if p is prime then x^p ≡ x mod p.


(i) Show that the statement is wrong if we drop the assumption that p is prime.
[Remember: All you need to do is to give a counterexample.]


(ii) Show, by giving an example, that if p is not prime, then x^p ≡ x mod p can still be true for some integers x with x is not −1, 0, 1.

Expert Solution
trending now

Trending now

This is a popular solution!

steps

Step by step

Solved in 3 steps

Blurred answer
Follow-up Questions
Read through expert solutions to related follow-up questions below.
Follow-up Question
●●●
2. Prove that for all a, b, m € Z \ {0} with gcd(a, b) = 1, ab|m iff a/m and b/m.
Before embarking on the proof, look at some examples, in order to understand what
this says, and to convince yourself that it indeed true, and that the assumption that
gcd(a, b) 1 is needed. This might also give you an idea for the proof. Also look at
some special cases, for example a = = 1.
=
"iff" stands for "if and only if". As above, this means that the proof should have two
parts, one for each direction. One direction is easy to prove, for the other direction
use Euclid's Lemma.
Transcribed Image Text:●●● 2. Prove that for all a, b, m € Z \ {0} with gcd(a, b) = 1, ab|m iff a/m and b/m. Before embarking on the proof, look at some examples, in order to understand what this says, and to convince yourself that it indeed true, and that the assumption that gcd(a, b) 1 is needed. This might also give you an idea for the proof. Also look at some special cases, for example a = = 1. = "iff" stands for "if and only if". As above, this means that the proof should have two parts, one for each direction. One direction is easy to prove, for the other direction use Euclid's Lemma.
Solution
Bartleby Expert
SEE SOLUTION
Similar questions
Recommended textbooks for you
Advanced Engineering Mathematics
Advanced Engineering Mathematics
Advanced Math
ISBN:
9780470458365
Author:
Erwin Kreyszig
Publisher:
Wiley, John & Sons, Incorporated
Numerical Methods for Engineers
Numerical Methods for Engineers
Advanced Math
ISBN:
9780073397924
Author:
Steven C. Chapra Dr., Raymond P. Canale
Publisher:
McGraw-Hill Education
Introductory Mathematics for Engineering Applicat…
Introductory Mathematics for Engineering Applicat…
Advanced Math
ISBN:
9781118141809
Author:
Nathan Klingbeil
Publisher:
WILEY
Mathematics For Machine Technology
Mathematics For Machine Technology
Advanced Math
ISBN:
9781337798310
Author:
Peterson, John.
Publisher:
Cengage Learning,
Basic Technical Mathematics
Basic Technical Mathematics
Advanced Math
ISBN:
9780134437705
Author:
Washington
Publisher:
PEARSON
Topology
Topology
Advanced Math
ISBN:
9780134689517
Author:
Munkres, James R.
Publisher:
Pearson,