Prove that converting the Higher-Order derivatives to the finite difference formula would be: f(x;) – 2f (x¡-1) + f(xi-2) (Ax)2 1) f"(x;) = "Backward Method" f(xi+2) – 2f(xi+1) + f(x;) 2) f"(xi) = "Forward Method" (Ax)2 f(xi+3) – 3f(xi+2)+ 3f(x;+1) – f(x;) (Ax)3 3) f'(x) = "Forward Method"

Advanced Engineering Mathematics
10th Edition
ISBN:9780470458365
Author:Erwin Kreyszig
Publisher:Erwin Kreyszig
Chapter2: Second-order Linear Odes
Section: Chapter Questions
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Prove that converting the Higher-Order derivatives to the finite difference formula
would be:
f(x) – 2f(xi-1) + f(x¡-2)
(Ax)2
1) f"(x;) =
"Backward Method"
f(xi+2) – 2f(x;+1) + f(x¡)
(Ax)2
2) f"(xi) =
"Forward Method"
f (xi+3) – 3f(xi+2) + 3f(xi+1) – f(x;)
(Ax)3
3) f"'(x;) =
"Forward Method"
Transcribed Image Text:Prove that converting the Higher-Order derivatives to the finite difference formula would be: f(x) – 2f(xi-1) + f(x¡-2) (Ax)2 1) f"(x;) = "Backward Method" f(xi+2) – 2f(x;+1) + f(x¡) (Ax)2 2) f"(xi) = "Forward Method" f (xi+3) – 3f(xi+2) + 3f(xi+1) – f(x;) (Ax)3 3) f"'(x;) = "Forward Method"
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