Prove that C is tangent to S at (0, -1, 1), considering that C has a vector-valued function 2 i+ 4 4 - 3)j+ cos(t – 2) k, - o
Prove that C is tangent to S at (0, -1, 1), considering that C has a vector-valued function 2 i+ 4 4 - 3)j+ cos(t – 2) k, - o
Algebra & Trigonometry with Analytic Geometry
13th Edition
ISBN:9781133382119
Author:Swokowski
Publisher:Swokowski
Chapter8: Applications Of Trigonometry
Section8.4: The Dot Product
Problem 32E
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![1.
Prove that C is tangent to S at (0, -1, 1), considering that C has a vector-valued function
3
G 2)i ( :); 1 coslt 2)k.
'4
R(t)
G-
3)j+ cos(t – 2) k,
- 00 <t < o0
-
4
and the surface S whose equation is x³ + y° + z° = xyz.](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F1c2025bf-6254-4a8d-b3c1-03cf2f28c594%2F6ad6c668-dd0d-4553-b968-01fe516bb0b1%2Fu7z0lm7_processed.png&w=3840&q=75)
Transcribed Image Text:1.
Prove that C is tangent to S at (0, -1, 1), considering that C has a vector-valued function
3
G 2)i ( :); 1 coslt 2)k.
'4
R(t)
G-
3)j+ cos(t – 2) k,
- 00 <t < o0
-
4
and the surface S whose equation is x³ + y° + z° = xyz.
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