Prove that at the point of intersection of the surfaces x² + y² = z², z = a_tan` (*) vhere y = x tan 0, the radius of curvature and torsion are given by a(2+0²) ³/2 (8+50+0¹) ¹/2 p = and o = a (8+50² +0¹) 6+0²

Advanced Engineering Mathematics
10th Edition
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Chapter2: Second-order Linear Odes
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Prove that at the point of intersection of the surfaces
(+)
where y = x tan_0, the radius of curvature and torsion are given by
a(2+0²) ³/2
(8+50+0¹) ¹/₂2
and & = ª(8+50² +0¹)
6+0²
p=
x² + y² = z², z = a_ tan`
Transcribed Image Text:Prove that at the point of intersection of the surfaces (+) where y = x tan_0, the radius of curvature and torsion are given by a(2+0²) ³/2 (8+50+0¹) ¹/₂2 and & = ª(8+50² +0¹) 6+0² p= x² + y² = z², z = a_ tan`
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