Prove that a minimum spanning tree of a graph component must include a shortest edge. It is possible, in Dijkstra’s algorithm, that an edge removed from the priority queue is not useful: it takes us to a previously visited node. Some of these extraneous edges can be avoided by not placing an edge in the priority queue if the destination has already been visited. Is it still possible to encounter an edge to a previously visited node?

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A: The solution for the above given question is given below:

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