Prove or disprove that if a, b E Q are rational numbers, then ab is also rational.

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Discrete Math

**Prove or disprove that if \( a, b \in \mathbb{Q} \) are rational numbers, then \( ab \) is also rational.**

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In this statement, we are asked to determine whether the product of two rational numbers is always rational. 

Explanation:

- Let \( a \) and \( b \) be rational numbers. By definition, rational numbers can be expressed in the form \( \frac{m}{n} \) where \( m \) and \( n \) are integers, and \( n \neq 0 \).
- Suppose \( a = \frac{p}{q} \) and \( b = \frac{r}{s} \), where \( p, q, r, s \) are integers and \( q, s \neq 0 \).
- Then, the product \( ab = \frac{p}{q} \times \frac{r}{s} = \frac{pr}{qs} \).
- Since the product of integers \( pr \) and \( qs \) is also an integer and \( qs \neq 0 \), \( ab \) is in the form \( \frac{x}{y} \) where \( x \) and \( y \) are integers, and \( y \neq 0 \).
- Hence, \( ab \) is a rational number.

Thus, the statement is true: the product of two rational numbers is always a rational number.
Transcribed Image Text:**Prove or disprove that if \( a, b \in \mathbb{Q} \) are rational numbers, then \( ab \) is also rational.** --- In this statement, we are asked to determine whether the product of two rational numbers is always rational. Explanation: - Let \( a \) and \( b \) be rational numbers. By definition, rational numbers can be expressed in the form \( \frac{m}{n} \) where \( m \) and \( n \) are integers, and \( n \neq 0 \). - Suppose \( a = \frac{p}{q} \) and \( b = \frac{r}{s} \), where \( p, q, r, s \) are integers and \( q, s \neq 0 \). - Then, the product \( ab = \frac{p}{q} \times \frac{r}{s} = \frac{pr}{qs} \). - Since the product of integers \( pr \) and \( qs \) is also an integer and \( qs \neq 0 \), \( ab \) is in the form \( \frac{x}{y} \) where \( x \) and \( y \) are integers, and \( y \neq 0 \). - Hence, \( ab \) is a rational number. Thus, the statement is true: the product of two rational numbers is always a rational number.
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