Prove: m/COD = 72°KAComplete the proof.It is given that m/AOBm/BOC = 66°. By them/AOC + m/CODAll rights reserved.42° and m/EOF= 66°. By the180°. After application of them/AOC 108°, and by theResetNextDELLFeedeZEOF ZBOC. Therefore,m/CODPienetas72°

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Answered: Prove: m/COD B DA 72° Complete the…

Elementary Geometry For College Students, 7e

7th Edition

ISBN:9781337614085

Author:Alexander, Daniel C.; Koeberlein, Geralyn M.

Publisher:Alexander, Daniel C.; Koeberlein, Geralyn M.

ChapterP: Preliminary Concepts

SectionP.CT: Test

Problem 1CT

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Prove: m/COD B DA 72° Complete the proof. It is given that m/AOB = 42° and m/EOF = 66°. By the m/BOC = 66°. By the m/AOC + m/COD = 180°. After application of the m/AOC = 108°, and by the ZEOF ZBOC. Therefore, m/COD = 72°