Prove: Given a polynomial p(x) with degree n and cЄ R, we have n p(x) = p(c) + Σ p(k) (c) k! k=1 -(x − c ) k. -
Prove: Given a polynomial p(x) with degree n and cЄ R, we have n p(x) = p(c) + Σ p(k) (c) k! k=1 -(x − c ) k. -
Advanced Engineering Mathematics
10th Edition
ISBN:9780470458365
Author:Erwin Kreyszig
Publisher:Erwin Kreyszig
Chapter2: Second-order Linear Odes
Section: Chapter Questions
Problem 1RQ
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![Prove: Given a polynomial p(x) with degree n and cЄ R, we have
n
p(x) = p(c) + Σ
p(k) (c)
k!
k=1
-(x − c ) k.
-](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F1d5e88e6-b1af-4aea-9b08-2dadd85f5e2c%2F30981daf-6c06-4140-b9af-3422d3e8a253%2Fqkg0m5g_processed.png&w=3840&q=75)
Transcribed Image Text:Prove: Given a polynomial p(x) with degree n and cЄ R, we have
n
p(x) = p(c) + Σ
p(k) (c)
k!
k=1
-(x − c ) k.
-
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