Prove -fpædas = - [ vpcx)av Vp(x)dV %3D using Gauss's divergence theorem dS = V. v(x)dV and V· (f(x)A(x)) = f (x) · A(x) + f (x)V · A(x)

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Prove
- p(x)ds = - | vp(x)dv
using Gauss's divergence theorem
-frx) • as = [ v• vcx)av
• v(x)dV
V .
and
V·(f(x)A(x)) = Vf(x)·A(x)+f (x)V · A(x)
Transcribed Image Text:Prove - p(x)ds = - | vp(x)dv using Gauss's divergence theorem -frx) • as = [ v• vcx)av • v(x)dV V . and V·(f(x)A(x)) = Vf(x)·A(x)+f (x)V · A(x)
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