i need help with all parts in this question asap Propylene is a critical petrochemical intermediate and the monomer for the production ofpolypropylene. Traditionally, propylene, along with other olefins such as ethylene, is produced from crudeoil fractionation. Since the shale revolution, there has been increased production of shale gas and shale oiland as a result, the demand for crude oil is reduced. While ethylene (the monomer for polyethylene) can bealternatively produced from shale-derived ethane rather easily using ethane cracker, the same crackingtechnology of shale-derived propane is rather challenging, resulting in a global shortage of propylene,termed the propylene gap.To produce propylene (C:Hs) from shale-derived propane (C:Hs), the dehydrogenation of propane isfollowed:C;Hg (g) 5 C,Hg (g) + H;(9)The reaction typically takes place over supported platinum catalysts. The thermochemical data for each ofthe species at 800 K are:C,HgC,H.H2AH;° (kJ/mol)-45.1469.8314.70s° (J/mol-K)359.28379.45159.55(1) What are the values of heat of reaction, entropy of reaction, and the Gibbs free energy of reaction atthis temperature (i.e., 800 K)? Please include the appropriate units.(2) What is the value of the gas phase equilibrium constant at this reaction temperature (800 K)?(3) If pure propane is fed at a reaction pressure of 1 atm, what is the equilibrium conversion under thiscondition (1 atm and 800 K)?(4) To increase the equilibrium conversion at 800 K, should we increase or decrease the reaction pressure?Report the equilibrium conversions of at least 2 pressures higher than 1 atm and 2 pressures lower than1 atm (a total of 4 points) to support your answer.(5) To increase the equilibrium conversion at 800 K, should we increase or decrease the reactiontemperature? Why?(6) In addition to changing reaction pressure and temperature, please propose two other approaches to shiftthe equilibrium to increase equilibrium conversion. Please provide the rationales of why yourapproaches could work.

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Propylene is a critical petrochemical intermediate and the monomer for the production of polypropylene. Traditionally, propylene, along with other olefins such as ethylene, is produced from crude oil fractionation. Since the shale revolution, there has been increased production of shale gas and shale oil and as a result, the demand for crude oil is reduced. While ethylene (the monomer for polyethylene) can be alternatively produced from shale-derived ethane rather easily using ethane cracker, the same cracking technology of shale-derived propane is rather challenging, resulting in a global shortage of propylene, termed the propylene gap. To produce propylene (C:Hs) from shale-derived propane (C3H3), the dehydrogenation of propane is followed: C,H3 (g) 5 C,Hg (g) + H;(9) The reaction typically takes place over supported platinum catalysts. The thermochemical data for each of the species at 800 K are: C,Hg C,H. H2 AH,° (kJ/mol) -45.14 69.83 14.70 s° (J/mol-K) 379.45 359.28 159.55 (1) What are the values of heat of reaction, entropy of reaction, and the Gibbs free energy of reaction at this temperature (i.e., 800 K)? Please include the appropriate units. (2) What is the value of the gas phase equilibrium constant at this reaction temperature (800 K)? (3) If pure propane is fed at a reaction pressure of 1 atm, what is the equilibrium conversion under this condition (1 atm and 800 K)? (4) To increase the equilibrium conversion at 800 K, should we increase or decrease the reaction pressure? Report the equilibrium conversions of at least 2 pressures higher than 1 atm and 2 pressures lower than 1 atm (a total of 4 points) to support your answer. (5) To increase the equilibrium conversion at 800 K, should we increase or decrease the reaction temperature? Why? (6) In addition to changing reaction pressure and temperature, please propose two other approaches to shift the equilibrium to increase equilibrium conversion. Please provide the rationales of why your approaches could work.