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Proposition 14.2.2 If A and B are denumerable sets, then AUB is demumerable. hónts. Proof Sketch on Hw7 Set A,= A'B, so A,UB = AUB and A,nB=Q. Case 1 - A, finile. k. -.. ett letz .... Case 2- A, infinite U (next class) A, denumerable -.. 2 4 6 B = {b.,b, bs, --} ... %D a nti fin)= if nis even. my idea about defiace the cuse 2 funcelon: Cnot Sure). Do noe kaow how to define the finition and More vitally, how to use the taverse to show st is bijective? res Gverse .

Proposition 14.2.2 If A and B are denumerable sets, then AUB is demumerable. hónts. Proof Sketch on Hw7 Set A,= A'B, so A,UB = AUB and A,nB=Q. Case 1 - A, finile. k. -.. ett letz .... Case 2- A, infinite U (next class) A, denumerable -.. 2 4 6 B = {b.,b, bs, --} ... %D a nti fin)= if nis even. my idea about defiace the cuse 2 funcelon: Cnot Sure). Do noe kaow how to define the finition and More vitally, how to use the taverse to show st is bijective? res Gverse .

Advanced Engineering Mathematics
Advanced Engineering Mathematics
10th Edition
ISBN:9780470458365
Author:Erwin Kreyszig
Publisher:Erwin Kreyszig
Chapter2: Second-order Linear Odes
Section: Chapter Questions
Problem 1RQ
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This question is almost done.Please prove wirh the ideas provided. There are some thoughts and requirements in the pic. I struggle with define the inverse and prove the bijection by identity . Please be specific about this.
3:57 PM Mon Nov 29 * © 32% I + : 0 Proposition 14.2.2 If A and B are denumerable sets, then AUB is demumerable. hints. Proof - on Hw7 Sketch Set A,= A'B, so A,UB = AUB and A,MB=Q. Case 1 - A, fimile k ktt letz f:2,>AUB B= $b,ibe,- Case 2- A, infiite U (nent class) A, denumerable %3D 2 4 6 odd if n is even. my idea about defince the cse 2 funcelon: Cnot sure). Do noe know how to define the funiton and More vitally, how to use the inverse Eo Ghow st is brjective? res Gverse . need do: for cuse I, maybe defle an Enverse , the compo site to show {t i's bújettiwe ☺ case 2: define a fmcton chd its inverse, by using amposite to Show it is bijective. use 10 49 Pro position 14.2.3
Transcribed Image Text:3:57 PM Mon Nov 29 * © 32% I + : 0 Proposition 14.2.2 If A and B are denumerable sets, then AUB is demumerable. hints. Proof - on Hw7 Sketch Set A,= A'B, so A,UB = AUB and A,MB=Q. Case 1 - A, fimile k ktt letz f:2,>AUB B= $b,ibe,- Case 2- A, infiite U (nent class) A, denumerable %3D 2 4 6 odd if n is even. my idea about defince the cse 2 funcelon: Cnot sure). Do noe know how to define the funiton and More vitally, how to use the inverse Eo Ghow st is brjective? res Gverse . need do: for cuse I, maybe defle an Enverse , the compo site to show {t i's bújettiwe ☺ case 2: define a fmcton chd its inverse, by using amposite to Show it is bijective. use 10 49 Pro position 14.2.3
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