2. A triangular parcel of land with vertices at R, S, and T was to be enclosed by a fence,but it was discovered that the surveyor's mark at S was missing. From a deed to theproperty, it was learned that the distance from T to R is 324 m, the distance from T toŠ is 506 m and the angle at R in the triangle is 125.4'. Determine the location of S byfinding the distance from R to S.

Given: RT=324 mST=506 m∠SRT=125.4° We need to find the distance from R to S.

property, it was learned that the distance from T to R is 324 m, the distance from T to Š is 506 m and the angle at R in the triangle is 125.4'. Determine the location of S by finding the distance from R to S.

property, it was learned that the distance from T to R is 324 m, the distance from T to Š is 506 m and the angle at R in the triangle is 125.4'. Determine the location of S by finding the distance from R to S.

Trigonometry (11th Edition)

11th Edition

ISBN:9780134217437

Author:Margaret L. Lial, John Hornsby, David I. Schneider, Callie Daniels

Publisher:Margaret L. Lial, John Hornsby, David I. Schneider, Callie Daniels

Chapter1: Trigonometric Functions

Section: Chapter Questions

Problem 1RE: 1. Give the measures of the complement and the supplement of an angle measuring 35°.

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Question

2. A triangular parcel of land with vertices at R, S, and T was to be enclosed by a fence,
but it was discovered that the surveyor's mark at S was missing. From a deed to the
property, it was learned that the distance from T to R is 324 m, the distance from T to
Š is 506 m and the angle at R in the triangle is 125.4'. Determine the location of S by
finding the distance from R to S.

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