Propanoic acid is a weak monoprotic acid with the formula HC3H;O2. It partially dissociates in water to release hydronium ions (H30*) and propanoate ions (C3H5O2-). We can abbreviate propanoic acid as “HPro" and the propanoate ion as Pro-. The acid-dissociation equilibrium for propanoic acid is described below. HPro (ag) + H2O () = H;O*(aq) + Pro- (ag) At 25°C, Ka, is 1.3 x 10-5 1) Write the mass-action expression for this reaction. (As a pure liquid, H20 is not included). The K value for this reaction is equal to Ka. 2) Use an "ICE“ (or "IAE" table to determine the concentrations of HPro, H3O*, and Pro1- in an aqueous solution of 0.160 M HPro. 3) Based on the value for [H3O*], calculate the pH of this 0.160 M HPro solution. 4) Calculate the value for [OH-] of this 0.160 M HPro solution.
Propanoic acid is a weak monoprotic acid with the formula HC3H;O2. It partially dissociates in water to release hydronium ions (H30*) and propanoate ions (C3H5O2-). We can abbreviate propanoic acid as “HPro" and the propanoate ion as Pro-. The acid-dissociation equilibrium for propanoic acid is described below. HPro (ag) + H2O () = H;O*(aq) + Pro- (ag) At 25°C, Ka, is 1.3 x 10-5 1) Write the mass-action expression for this reaction. (As a pure liquid, H20 is not included). The K value for this reaction is equal to Ka. 2) Use an "ICE“ (or "IAE" table to determine the concentrations of HPro, H3O*, and Pro1- in an aqueous solution of 0.160 M HPro. 3) Based on the value for [H3O*], calculate the pH of this 0.160 M HPro solution. 4) Calculate the value for [OH-] of this 0.160 M HPro solution.
Chemistry
10th Edition
ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Chapter1: Chemical Foundations
Section: Chapter Questions
Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
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![In a reaction, 80.0 mL of 0.160 M HPro was reacted with 20.0 mL of 0.140 M NAOH. (Na* is a
spectator ion and has been omitted.)
HPro (aq) + OH- (ag) → H20 () + Pro- (ag)
6) Identify the limiting reagent, and find the concentrations of HPro, NaOH, and NaPro at the end
of this "big change" reaction. (The LR concentration will be zero.)
7) Using your values of HPTO and NaPro in the answer to the previous problem, plug into the K,
equation to solve for the value of [H*].
8) Calculate the pH of this final solution.
9) Write the dissociation reaction for the weak base LiPro (Pro) in water.
10) Write the mass action expression for this equation, which is equal to Ko.
11) Since Kw = Ka x Ko, solve for the mathematical value of Kp.
12) Calculate the following values for a 0.138 M Ca(Pro)2 solution:
(a) the [OH] in a 0.138 M Ca(Pro)2 solution. (Use an “ICE" table)
(b) the pH of a 0.138 M Ca(Pro)2 solution.](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2Fd9f79989-d9c4-46f2-a3af-be71864f1886%2Ff90b5535-a87a-49cc-bb4d-13b0adda2720%2Fp2i8g68_processed.png&w=3840&q=75)
Transcribed Image Text:In a reaction, 80.0 mL of 0.160 M HPro was reacted with 20.0 mL of 0.140 M NAOH. (Na* is a
spectator ion and has been omitted.)
HPro (aq) + OH- (ag) → H20 () + Pro- (ag)
6) Identify the limiting reagent, and find the concentrations of HPro, NaOH, and NaPro at the end
of this "big change" reaction. (The LR concentration will be zero.)
7) Using your values of HPTO and NaPro in the answer to the previous problem, plug into the K,
equation to solve for the value of [H*].
8) Calculate the pH of this final solution.
9) Write the dissociation reaction for the weak base LiPro (Pro) in water.
10) Write the mass action expression for this equation, which is equal to Ko.
11) Since Kw = Ka x Ko, solve for the mathematical value of Kp.
12) Calculate the following values for a 0.138 M Ca(Pro)2 solution:
(a) the [OH] in a 0.138 M Ca(Pro)2 solution. (Use an “ICE" table)
(b) the pH of a 0.138 M Ca(Pro)2 solution.
![Propanoic acid is a weak monoprotic acid with the formula HC3H;O2. It partially dissociates in
water to release hydronium ions (H30*) and propanoate ions (C3H5O2-). We can abbreviate
propanoic acid as “HPro" and the propanoate ion as Pro-. The acid-dissociation equilibrium for
propanoic acid is described below.
HPro (ag) + H2O () = H;O*(aq) + Pro- (ag)
At 25°C, Ka, is 1.3 x 10-5
1) Write the mass-action expression for this reaction. (As a pure liquid, H20 is not included).
The K value for this reaction is equal to Ka.
2) Use an "ICE“ (or "IAE" table to determine the concentrations of HPro, H3O*, and Pro1- in an
aqueous solution of 0.160 M HPro.
3) Based on the value for [H3O*], calculate the pH of this 0.160 M HPro solution.
4) Calculate the value for [OH-] of this 0.160 M HPro solution.
5) The percent dissociation of a weak acid depends on the initial concentration of HA ([HA]0).
It is found using this value and the equilibrium concentration of {H*] ([H*]e).
([H*]e
[HA]o,
Calculate the percent dissociation of 0.160 M HPro.
% dissociation =
(100%)](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2Fd9f79989-d9c4-46f2-a3af-be71864f1886%2Ff90b5535-a87a-49cc-bb4d-13b0adda2720%2F0oi7wl6_processed.png&w=3840&q=75)
Transcribed Image Text:Propanoic acid is a weak monoprotic acid with the formula HC3H;O2. It partially dissociates in
water to release hydronium ions (H30*) and propanoate ions (C3H5O2-). We can abbreviate
propanoic acid as “HPro" and the propanoate ion as Pro-. The acid-dissociation equilibrium for
propanoic acid is described below.
HPro (ag) + H2O () = H;O*(aq) + Pro- (ag)
At 25°C, Ka, is 1.3 x 10-5
1) Write the mass-action expression for this reaction. (As a pure liquid, H20 is not included).
The K value for this reaction is equal to Ka.
2) Use an "ICE“ (or "IAE" table to determine the concentrations of HPro, H3O*, and Pro1- in an
aqueous solution of 0.160 M HPro.
3) Based on the value for [H3O*], calculate the pH of this 0.160 M HPro solution.
4) Calculate the value for [OH-] of this 0.160 M HPro solution.
5) The percent dissociation of a weak acid depends on the initial concentration of HA ([HA]0).
It is found using this value and the equilibrium concentration of {H*] ([H*]e).
([H*]e
[HA]o,
Calculate the percent dissociation of 0.160 M HPro.
% dissociation =
(100%)
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